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FZOU
Helper IV
Helper IV

Dax Soustract DATE

Hello,

I need your help guys to achieve a formula.

 

I have a column that containt "Year-Month" for exp :

YearMonth

2019-01

2019-02

2019-03

N..

 

I have another column that contains number of monthsf for exp :

 

MonthN

10 

15 

N..

 

The demanded task is to have the difference between the two columns for exp : 

 

"2019-10" - 9 = "2019-01"

 

Anyone have an idea how to do it please !

 

1 ACCEPTED SOLUTION

Hi @FZOU ,

Can you change the data type of column "YearMonth" from Text to Date? If yes, maybe you could try this:

Column =
DATE ( YEAR ( 'Table'[YearMonth] ), MONTH ( 'Table'[YearMonth] ) - 'Table'[MonthN], DAY ( 'Table'[YearMonth] ) )

And then format the new column as "yyyy-mm".

3.PNG 

Best Regards,
Xue Ding
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

9 REPLIES 9
amitchandak
Super User
Super User

@FZOU 

Try like

format(date(year(left([month-year]),4),month(right([month-year]),2)-9,1),"YYYY-MM")

 

Here -9 is the number you want to subtract

 

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@amitchandak  it's impssible to format text as date !

Hi @FZOU ,

Can you change the data type of column "YearMonth" from Text to Date? If yes, maybe you could try this:

Column =
DATE ( YEAR ( 'Table'[YearMonth] ), MONTH ( 'Table'[YearMonth] ) - 'Table'[MonthN], DAY ( 'Table'[YearMonth] ) )

And then format the new column as "yyyy-mm".

3.PNG 

Best Regards,
Xue Ding
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

@v-xuding-msftThank you for your help,it's work perfectly 🙂

Try like

format(date(year(left([month-year]),4),month(mid([month-year],search("-",[month-year],1,0)+1,len([month-year])))-9,1),"YYYY-MM")

 

To get the correct value of the month please check this separately - mid([month-year],search("-",[month-year],1,0)+1,len([month-year]))

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Greg_Deckler
Community Champion
Community Champion

Perhaps:

 

Column =
  VAR __YearMonth = VALUE(SUBSTITUTE([YearMonth],"-",""))
  VAR __NewYearMonth = (__YearMonth - [MonthN]) & ""
RETURN
  LEFT(__NewYearMonth,4) & "-" & RIGHT(__NewYearMonth,2)


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@Greg_Decklerthank you for your response but i had this result 

 

NewYearMonth.PNG

 

Right, forgot the padded zero, try this one:

 

Column =
  VAR __YearMonth = VALUE(SUBSTITUTE([YearMonth],"-",""))
  VAR __NewYearMonth = (__YearMonth - [MonthN]) & ""
RETURN
  LEFT(__NewYearMonth,4) & "-" & FORMAT(RIGHT(__NewYearMonth,2),"0#")

 

Might be ## or 0#, one of them or both give a padded right-zero. 



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@ me in replies or I'll lose your thread!!!
Instead of a Kudo, please vote for this idea
Become an expert!: Enterprise DNA
External Tools: MSHGQM
YouTube Channel!: Microsoft Hates Greg
Latest book!:
DAX For Humans

DAX is easy, CALCULATE makes DAX hard...

@Greg_Deckleri keep get the same wrong result

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