Forum Discussion
Date Diff and group
- 6 years ago
Hi Anonymous ,
I create an example.
ID Open Date Target Date 1 11/1/2019 11/19/2019 2 11/2/2019 11/21/2019 3 11/3/2019 11/18/2019 4 11/4/2019 11/20/2019 5 11/5/2019 11/22/2019 6 11/6/2019 11/30/2019 Create measures like so:
IsOverdue = IF ( TODAY () > MAX ( 'Table'[Target Date] ), 1, 0 )Count of IsOverdue = SUMX ( 'Table', [IsOverdue] )Or, you can create measures like so:
DateDiff of Day = DATEDIFF ( MAX ( 'Table'[Target Date] ), TODAY (), DAY )IsOverdue 2 = IF ( [DateDiff of Day] > 0, 1, 0 )Count of IsOverdue 2 = SUMX ( 'Table', [IsOverdue 2] )Best Regards,
Icey
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Hi Anonymous ,
create a calculated column (New column) with the overdue calculation.
Then you can treat the column like any other column.
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Hi Anonymous ,
i think you want something like this
DaysOverdue =
VAR Due =
DATEDIFF ( 'Table'[Date]; TODAY (); DAY )
RETURN
IF ( Due > 0; Due; BLANK () )
If I answered your question, please mark my post as solution, this will also help others.
Please give Kudos for support.