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Andy6001
Frequent Visitor

DAX

Hi, I'm new to DAX and I'm struggling to understand the following:

 

I have two columns in the same table:

CID (a unique card ID)

UID (a unique user id)

 

I want to evaluate all instances where a uniquie UID has more than one CID.

In a pivot table this would be straight fiorward but I'm completely stumped in Power BI.

 

I can do this in  standard table but I would like it as a measure that I can then stitch into a wider measure.

 

Can anyone help?

Thanks,

Andy

1 ACCEPTED SOLUTION
v-yulgu-msft
Employee
Employee

Hi @Andy6001 ,

 

Suppose this is your sample table.

1.PNG

 

To display those records where each unique UID has more than one CID and count the number of UID which meets such a condition, please refer to below measures:

count CID =
IF (
    CALCULATE ( DISTINCTCOUNT ( Sheet9[CID] ), ALL ( Sheet9[CID] ) ) > 1,
    CALCULATE ( DISTINCTCOUNT ( Sheet9[CID] ), ALL ( Sheet9[CID] ) ),
    BLANK ()
)

Count UID =
IF (
    [count CID] = BLANK (),
    BLANK (),
    CALCULATE (
        DISTINCTCOUNT ( Sheet9[UID] ),
        FILTER ( ALLSELECTED ( Sheet9 ), [count CID] > 1 )
    )
)

1.PNG

Best regards,

Yuliana Gu

Community Support Team _ Yuliana Gu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

1 REPLY 1
v-yulgu-msft
Employee
Employee

Hi @Andy6001 ,

 

Suppose this is your sample table.

1.PNG

 

To display those records where each unique UID has more than one CID and count the number of UID which meets such a condition, please refer to below measures:

count CID =
IF (
    CALCULATE ( DISTINCTCOUNT ( Sheet9[CID] ), ALL ( Sheet9[CID] ) ) > 1,
    CALCULATE ( DISTINCTCOUNT ( Sheet9[CID] ), ALL ( Sheet9[CID] ) ),
    BLANK ()
)

Count UID =
IF (
    [count CID] = BLANK (),
    BLANK (),
    CALCULATE (
        DISTINCTCOUNT ( Sheet9[UID] ),
        FILTER ( ALLSELECTED ( Sheet9 ), [count CID] > 1 )
    )
)

1.PNG

Best regards,

Yuliana Gu

Community Support Team _ Yuliana Gu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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