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Hi all,
I'm trying since 4 hours from now to achieve this formula. Without any success...
I'm trying with earlier function to retrieve the total amount into a quarter from a previous quarter in the column.
Index | Quarter | Project | Combo Project | Index Combo | Value | Value Earlier |
1 | Q2 | 15666666 | Q215666666 | 1 | 10 | 0 |
2 | Q2 | 15666666 | Q215666666 | 1 | 20 | 0 |
3 | Q2 | 15666666 | Q215666666 | 1 | 30 | 0 |
4 | Q3 | 15666666 | Q215666666 | 4 | 40 | 60 |
5 | Q3 | 15666666 | Q215666666 | 4 | 50 | 0 |
6 | Q3 | 15666666 | Q215666666 | 4 | 60 | 0 |
In Excel I woul have perform SUMIFS on "Value Earlier" column with the argument "Q2", but this is not possible in PowerBI as row is referenced under "Q3".
I can't plug a specfic number under the earlier function to take the previous "Index Combo" Value, as I can have multiple values in each quarter for each projects.
Thanks in advance, I think I've explored all combination of earlier over there.
WaX.
Solved! Go to Solution.
Try new columns like
Quarter No = right([Quarter],1)
Value Earlier = sumx(filter(table,table[Project]=earlier(table[Project]) && [Quarter No] =earlier([Quarter No])-1),[Value])
But if want index 4 only to have this new value , then additional logic need to be added to find min of the qtr
Perhaps:
Value Earlier Column =
VAR __Quarter = [Quarter]
VAR __PreviousQuarter =
SWITCH(__Quarter,
"Q1","Q4",
"Q2","Q1",
"Q3","Q2",
"Q1"
)
RETURN
SUMX(FILTER('Table',[Quarter] = __PreviousQuarter),[Value])
Hi @WaXpEd ,
Are you looking for the follwoing solution as shown below:
If this helps and resolves the issue, appreciate a Kudos and mark it as a Solution! 🙂
Thanks,
Pragati
Try new columns like
Quarter No = right([Quarter],1)
Value Earlier = sumx(filter(table,table[Project]=earlier(table[Project]) && [Quarter No] =earlier([Quarter No])-1),[Value])
But if want index 4 only to have this new value , then additional logic need to be added to find min of the qtr
Thanks a lot @amitchandak very helpful, it works now. Obvious with only numbers now you've spotted this!
Thanks again.
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