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jcox
Frequent Visitor

DATEDIFF when using Dates in a Column and using the TODAY() Function

So I feel like I've been close to finding a solution for a while, but I've been trying to write a measure that will take todays date from the TODAY() function, and subtract the date from a column already set up in a query in my data set and the end result I want to see is the amount of days in between. What I'm trying to find is essentially TODAY() - [Last Sales Stage Date] = Days between. I can't write it like that though so I was wondering if anyone has had any luck. Thanks!

 

-Jonathon

4 REPLIES 4
Eric_Zhang
Microsoft Employee
Microsoft Employee


@jcox wrote:

So I feel like I've been close to finding a solution for a while, but I've been trying to write a measure that will take todays date from the TODAY() function, and subtract the date from a column already set up in a query in my data set and the end result I want to see is the amount of days in between. What I'm trying to find is essentially TODAY() - [Last Sales Stage Date] = Days between. I can't write it like that though so I was wondering if anyone has had any luck. Thanks!

 

-Jonathon


@jcox

 

When trying to refer a column in a measure, you have to aggregate it to get a scalar value. Something like

Days between = DATEDIFF(TODAY(),MAX('table'[Last Sales Stage Date]),DAY)
jahida
Impactful Individual
Impactful Individual

You can do it without another calculated column, something like: (assuming you know for sure there are no dates today)

 

MeasureDaysBetween = SUMX(Table, DATEDIFF(Table[Last Sales Stage Date], TODAY(), DAY))

Sean
Community Champion
Community Champion

@jcox You have to create a Calculated COLUMN and your formula would look something like this...

 

Day Between COLUMN = DATEDIFF ( [Last Sales Stage Date], today(), DAY )

http://www.sqlbi.com/articles/calculated-columns-a​nd-measures-in-dax/

 

@smoupre's solution also works but again NOTE it has to be a COLUMN not a Measure! (you say you are trying to write a Measure)

 

Greg_Deckler
Super User
Super User

This will work:

 

(TODAY()-[Date].[Date])*1.

This will avoid errors you can get with DATEDIFF depending upon starting date being larger than end date. 


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