Forum Discussion
Create visual from filtered data
Hi
In the screen-shot below, I'm trying to create a pie chart (or similar) from my filtered data.
(1) The filtered numbers are being displayed in the "Card with States" by OKViz.
(2) & (3) are the cards.
(4) 3 Jockey/Trainer combinations contibuted to the 16 shown in (3).
The charts I need to show would be 384/16 as a percentage and 16/3 as a percentage.
Any ideas on how to acheive this will be appreciated.
Thanks, Mark.
Hi
Thanks for helping.
What wound up working for me was the following:
primaryFiltered = CALCULATE(COUNT(Sheet1[Colour]), ALLEXCEPT(Sheet1, Sheet1[Substance], Sheet1[Population]))
secondaryCount = COUNT(Sheet1[Colour])
Regards, Mark.
9 Replies
- AbduvaliSkilled Sharer
Hi Skemaz,
You can use a calculated measure to achieve what you need but I need some clarity on points below to help you out:
- Where the following values are coming from 384 and 16???
- Are they in different columns?
- And how do you differentiate between horses and race values?
- 16/3....what does number 3 represent???
Regards
Abduvali
- SkemazAdvocate II
Hi Abduvali
Thanks for your prompt reply.
The user selects filters in the "Race Filters" this reduces the number shown in (2) in the screen-shot. The number is just a single value in a Card. I have edited the filters interactions so that the filters in "Race Filters" apply to card (2) and (1).
However, the filters in "Horse Filters" only affect (1) and not (2).
The value could come from any field, but I have used a count of the "age" field to get the number.
In the screen-shot, (4) shows 3 rows representing the Jockey and Horse combination which is the 3 you asked about.
Thanks, Mark.
- AbduvaliSkilled Sharer
OK then create 4 measures:
- Race Measure = Calculate(SUM(YourTable[YourValue]),YourTable[RaceColumn] = "Race")
- this will let you get you 384 value, its same as the way you filtering it only by Race in that card
- Horse Measure = Calculate(SUM(YourTable[YourValue]),YourTable[RaceColumn] = "Horse")
- this will let you get you 16 value, its same as the way you filtering it only by Horse in that card
- Then create 3rd measure:
- % Measure = [Race Measure] / [Horse Measure]
- then select display as Percentage from Modelling tab / Data type
- % Measure = [Race Measure] / [Horse Measure]
- For the last one you will need another measure:
- Jockey Measure = [Horse Measure] / Distinctcount(YourTable[JockeyColumn])
- then select display as Percentage from Modelling tab / Data type
- Jockey Measure = [Horse Measure] / Distinctcount(YourTable[JockeyColumn])
I hope this will help if you have any questions let me know.
Regards
Abduvali
- Race Measure = Calculate(SUM(YourTable[YourValue]),YourTable[RaceColumn] = "Race")