Forum Discussion
Create visual from filtered data
- 8 years ago
Hi
Thanks for helping.
What wound up working for me was the following:
primaryFiltered = CALCULATE(COUNT(Sheet1[Colour]), ALLEXCEPT(Sheet1, Sheet1[Substance], Sheet1[Population]))
secondaryCount = COUNT(Sheet1[Colour])
Regards, Mark.
Hi Abduvali
Thanks for your prompt reply.
The user selects filters in the "Race Filters" this reduces the number shown in (2) in the screen-shot. The number is just a single value in a Card. I have edited the filters interactions so that the filters in "Race Filters" apply to card (2) and (1).
However, the filters in "Horse Filters" only affect (1) and not (2).
The value could come from any field, but I have used a count of the "age" field to get the number.
In the screen-shot, (4) shows 3 rows representing the Jockey and Horse combination which is the 3 you asked about.
Thanks, Mark.
OK then create 4 measures:
- Race Measure = Calculate(SUM(YourTable[YourValue]),YourTable[RaceColumn] = "Race")
- this will let you get you 384 value, its same as the way you filtering it only by Race in that card
- Horse Measure = Calculate(SUM(YourTable[YourValue]),YourTable[RaceColumn] = "Horse")
- this will let you get you 16 value, its same as the way you filtering it only by Horse in that card
- Then create 3rd measure:
- % Measure = [Race Measure] / [Horse Measure]
- then select display as Percentage from Modelling tab / Data type
- % Measure = [Race Measure] / [Horse Measure]
- For the last one you will need another measure:
- Jockey Measure = [Horse Measure] / Distinctcount(YourTable[JockeyColumn])
- then select display as Percentage from Modelling tab / Data type
- Jockey Measure = [Horse Measure] / Distinctcount(YourTable[JockeyColumn])
I hope this will help if you have any questions let me know.
Regards
Abduvali