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hi
I have following table
Date Col 1 Col 2 Col 3
01-01-2020 43566 100000 2
01-12-2020 23456 100000 3
30-06-2021 12345 100000 4
31-10-2022 43566 100000 2
30-11-2022 23456 100000 3
31-12-2022 12345 100000 4
User does the following :
Using Power Bi visual slicer , user keeps records only for year 2022 .
Following SHOULD HAPPEN
2) Automatically a dynamic table should be created as indicated below with an additonal last row with following calculations
2.1) Last row date should be latest date of the filtered data
2.2 ) COl 1 of Last row should be (Value in col 1 of latest date * sum of col 3 of filtered rows )
Date Col 1 Col 2 Col 3
31-10-2022 43566 100000 2
30-11-2022 23456 100000 3
31-12-2022 12345 100000 4
31-12-2022 12345*9
Hi @ashwinkolte ,
Please refer to my pbix file.
let
Source = Table,
#"2022" = Table.SelectRows(Source, each Date.Year([Date])=2022),
Custom3 = Table.ToRecords(#"2022"),
MaxDate = List.Max(Source[Date]),
MaxCol1Value = Table.SelectRows(Source,each [Date]=MaxDate)[Col 1]{0},
Total = List.Sum(Table.SelectRows(Source, each Date.Year([Date])<>2022)[Col 3]),
Custom1 = Total,
Custom2 = {[Date = MaxDate,Col 1=MaxCol1Value*Total,Col 2=null,Col 3=null]},
Custom4 = Table.FromRecords(List.Combine({Custom3,Custom2}))
in
Custom4
How to Get Your Question Answered Quickly
If it does not help, please provide more details with your desired output and pbix file without privacy information (or some sample data) .
Best Regards
Community Support Team _ Polly
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Dear v-rongtiep-msft
Thanks for your response. However as mentioned in my requirement , I need a dynamic table to be created when a user slices data on BI visual and depending on which records user selects in table 1. Is that possible ?
Hi @ashwinkolte ,
The dynamic addition of rows does not seem to be very feasible.
Best Regards
Community Support Team _ Polly
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
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