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Hello. Look at the table below.
| Application |
| 1st application |
| 12th application |
| 3rd application |
| 7th application |
| 11 application |
I need to create a new column that extracts only the number from the previous column. Generally I would use LEFT, but as some numbers have different digits, this option would not work. The table would have to look like this:
| Application | Index |
| 1st application | 1 |
| 12th application | 12 |
| 3rd application | 3 |
| 7th application | 7 |
| 11 application | 11 |
Solved! Go to Solution.
Hi @LeandroDeodato ,Thank you for your quick reply, I will add more.
Hi @jobf ,
The Table data is shown below:
Use the following DAX expression to create a column
Column =
VAR _len =
LEN ( [Application] )
VAR _table =
ADDCOLUMNS (
GENERATESERIES ( 1, _len, 1 ),
"Char", IFERROR ( VALUE ( MID ( [Application], [Value], 1 ) ), BLANK () )
)
RETURN
VALUE ( CONCATENATEX ( _table, [Char] ) )
Best Regards,
Wenbin Zhou
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @LeandroDeodato ,Thank you for your quick reply, I will add more.
Hi @jobf ,
The Table data is shown below:
Use the following DAX expression to create a column
Column =
VAR _len =
LEN ( [Application] )
VAR _table =
ADDCOLUMNS (
GENERATESERIES ( 1, _len, 1 ),
"Char", IFERROR ( VALUE ( MID ( [Application], [Value], 1 ) ), BLANK () )
)
RETURN
VALUE ( CONCATENATEX ( _table, [Char] ) )
Best Regards,
Wenbin Zhou
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
use data transform and split colummn using "space caracter" delimiter, also substitute "ª" caracter to " "
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