Forum Discussion
Counting column values for a matrix visual
Hi All,
For a matrix visual, I'm looking to calculate the number of rows for a particular column.
Can someone suggest a dax measure for this please?
Hi pg9 ,
Please try:
Measure = CALCULATE(COUNT(Sheet1[EmpIID]),FILTER(ALL(Sheet1),[Attribute] in ALLSELECTED('Sheet1 (2)'[Attribute]) &&[Value] in ALLSELECTED('Sheet1 (2)'[Value])))Final output:
Best Regards,
Jianbo Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
7 Replies
Hi pg9 ,
Sorry for that the information you have provided is not making the problem clear to me. Can you please share more details to help us clarify your scenario?
Please provide me with more details about your table and your problem or share me with your pbix file after removing sensitive data.
Refer to:
How to provide sample data in the Power BI Forum
How to Get Your Question Answered Quickly
Best Regards,
Jianbo Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Please find the step by step below
Step 1 - I have pivoted the table and used matrix visual to view it. Below is how the table looks initially. I have used count of emplid to count the data.
Step 2 - As I start choosing the selections from the field selections, the count keeps increasing. Please find the reference below
Requirement - I want to calculte the number of records in the emplID column alone.
Can you suggest how this can be achieved?
Please let me know if you need further input on this
Note - I have duplicate emplID records. So I'm not allowed to use distinct count.
Hi pg9 ,
By calculating it separately do you mean making its value independent of slicer and calculating the value in the table directly? If so, you can use the ALL function, like this:
Measure = COUNTX(All('Table'[EmpID]'),[EmpID])Refer to:
ALL function (DAX) - DAX | Microsoft Learn
Best Regards,
Jianbo Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
