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CSRiotech
Frequent Visitor

Count the number of unique entries(string) per category

Hi All,

 

I have the following table structure:

ItemgroupItemno
A1
A2
A2
B3
B3
B3
C4
C5
C6

 

And the output I need is a calculated column that contains the unique number of Itemno for each Itemgroup.
Like this:

ItemgroupItemnoUnique Entries of Itemno
A12
A22
A22
B31
B31
B31
C43
C53
C63

 

I think the answer would be some sort of combination of SUMMARIZE/GROUPBY and DISTINCT COUNTROWS.  I just cannot figure this one out myself. 

Thanks in advance!

1 ACCEPTED SOLUTION
v-yangliu-msft
Community Support
Community Support

Hi  @CSRiotech ,

Here are the steps you can follow:

1. Create calculated column.

Unique Entries of Itemno =
CALCULATE(
    DISTINCTCOUNT('Table'[Itemno]),
    FILTER(ALL('Table'),
    'Table'[Itemgroup]=EARLIER('Table'[Itemgroup])))

2. Result:

vyangliumsft_0-1668734210068.png

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

View solution in original post

1 REPLY 1
v-yangliu-msft
Community Support
Community Support

Hi  @CSRiotech ,

Here are the steps you can follow:

1. Create calculated column.

Unique Entries of Itemno =
CALCULATE(
    DISTINCTCOUNT('Table'[Itemno]),
    FILTER(ALL('Table'),
    'Table'[Itemgroup]=EARLIER('Table'[Itemgroup])))

2. Result:

vyangliumsft_0-1668734210068.png

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

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