Count duplicates only once in a column

[Blizzard]

Hi all,

I want to identify in a column (not as a measure) all values for a specific ID only once. 

ID	Date	Unique
10	09.11.2017	YES
2	01.12.2017	YES
10	11.11.2011	NO

The respective formular in Excel works fine as follows:

=IF(MATCH(A4,A:A,0)=ROW(),"YES","NO")

What I wanted to do is, that the last entry of an ID is identified as unique (column C) and all past values of the same ID should be marked as "no". Therefore the DISTINCTCOUNT formular with filter is not working. In that case, all double values would be counted > 1. For ID 10 the outcoume would be 2 for both rows but I want to count ID excatly one time as unique.

I dont want to delete duplicate rows.

Does anyone has an idea how to solve that problem?

Regards

Michael

[Zubair_Muhammad · Accepted solution]

Hi @Blizzard

Please try this column

Column =
VAR IDCount =
    CALCULATE ( COUNTROWS ( Table1 ), ALLEXCEPT ( Table1, Table1[ID] ) ) = 1
VAR Last_Date =
    Table1[Date]
        = CALCULATE ( MAX ( Table1[Date] ), ALLEXCEPT ( Table1, Table1[ID] ) )
RETURN
    IF ( OR ( IDCount, Last_Date ), "Yes", "No" )

[Blizzard]

Hi @Zubair_Muhammad,

your code is working as well. For the first step I used the code presented here.

Unfortunately I double posted my question :(. But as your formular is working as well, I`m confident that I can use it for the next step in another calcualtion.

Thanks a lot,

Michael