Forum Discussion
Count Total Distinct Dates for a Month in a Production Table
- 5 years ago
Ok, you are using Fecha in the visual instead of Date so we need to do the ALL( ) on Fecha:
CaCantidadias Tabla VeVentas CALCULATE( DIDISTINCTCOUNTroraentas[CAB_FECHA]), ALL(Calendario[FeFecha )It is probably best to only have one column with the date in the calendar table rather that, to avoid potential confusion like here.
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Hi jorgus
Assuming the fields you use in the visuals are from the calendar table, try:
Cantidad Dias Tabla Ventas =
CALCULATE(
DISTINCTCOUNT(ora_ventas[CAB_FECHA]),
ALL(CalendarT[Date])
)
Please mark the question solved when done and consider giving kudos if posts are helpful.
Contact me privately for support with any larger-scale BI needs, tutoring, etc.
Cheers
hi AlB thanks, for you reply
I change the measure, but the problem persist
Cantidad Dias Tabla Ventas =
CALCULATE(
DISTINCTCOUNT(ora_ventas[CAB_FECHA]),
ALL(Calendario[Date])
)
My Calendar Table:
Calendario =
VAR Days = CALENDARAUTO()
RETURN ADDCOLUMNS (
Days,
"Fecha", FORMAT([Date], "DD/MM/YYYY"),
"Año", YEAR ([Date]),
"Año Mes Codigo", (YEAR([Date]) * 100) + MONTH ([Date]),
"Año Mes Corto", FORMAT ([Date], "YYYY-MMM"),
"Año Mes", FORMAT ([Date], "YYYY-MMMM"),
"Trimestre Nro", TRUNC ( ( MONTH ( [Date] ) - 1 ) / 3 ) + 1,
"Trimestre", "T" & TRUNC ( ( MONTH ( [Date] ) - 1 ) / 3 ) + 1,
"Trimestre Quarter Nro", FORMAT([Date], "Q"),
"Trimestre Quarter", "T" & FORMAT([Date], "Q"),
"Trimestre Quarter Año", "T" & FORMAT([Date], "Q-YYYY"),
"Mes", MONTH ([Date]),
"Mes Nombre Año", FORMAT ([Date], "MMMM YYYY"),
"Mes Nombre", FORMAT ([Date], "MMMM"),
"Mes Corto", FORMAT ([Date], "MMM"),
"Mes Año", FORMAT ([Date], "mmm yy"),
"Dia Numero", Day ([Date])
)
The relationship
For the visual matrix it shows: Mes Corto, Fecha Corta 2, Cantidad Dias Tabla Ventas
- AlB5 years ago
Community Champion
Ok, you are using Fecha in the visual instead of Date so we need to do the ALL( ) on Fecha:
CaCantidadias Tabla VeVentas CALCULATE( DIDISTINCTCOUNTroraentas[CAB_FECHA]), ALL(Calendario[FeFecha )It is probably best to only have one column with the date in the calendar table rather that, to avoid potential confusion like here.
Please mark the question solved when done and consider giving kudos if posts are helpful.
Contact me privately for support with any larger-scale BI needs, tutoring, etc.
Cheers