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Anonymous
Not applicable

Count Distinct by Date

Hi,

 

I want to find the distinct count of customers who have visited a shop everyday. Is there a specific DAX or Mquery?

My plan is to create a column chart to find unique customers per day grouped monthly.  

 

Eg: "Sam" visits Wmart today thrice and tomorrow twice. I want him to be counted once today and again counted once tomorrow. Similarly for all customers and then add the values monthly.

 

Would appreciate if anyone could show me how to do it.

 

Regards,

Ruban 

1 ACCEPTED SOLUTION
v-lili6-msft
Community Support
Community Support

hi, @Anonymous @ryan_mayu

Eg: "Sam" visits Wmart today thrice and tomorrow twice. I want him to be counted once today and again counted once tomorrow. Similarly for all customers and then add the values monthly.

So times of Sam visits Shop these two days is 2, not just distinctcount result is 1.

You could try to use DISTINCTCOUNT and SUMX to create a measure like this

Measure 2 = var _table=SUMMARIZE('Table','Table'[Shop],'Table'[Date],"distinctcount",DISTINCTCOUNT('Table'[Customer]))
return
SUMX(_table,[distinctcount])

Result:

3.JPG

Regards,

Lin

 

 

Community Support Team _ Lin
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

6 REPLIES 6
fsadiq
Frequent Visitor

Hello All, I have a list of dates and Names. Each name has random dates based on their daily activities i.e A name has like 3 same date because he/she carried out 3 activities that same day . I already sorted the datasets by month using the slicer viz. I want to count all unique dates in a month i.e When you select may, I want to have unique number of days in may using Card Viz. Viz: https://ibb.co/sCm2dkP Table: https://ibb.co/1JqhgRR I made the Month sorting using end column. Thanks
v-lili6-msft
Community Support
Community Support

hi, @Anonymous @ryan_mayu

Eg: "Sam" visits Wmart today thrice and tomorrow twice. I want him to be counted once today and again counted once tomorrow. Similarly for all customers and then add the values monthly.

So times of Sam visits Shop these two days is 2, not just distinctcount result is 1.

You could try to use DISTINCTCOUNT and SUMX to create a measure like this

Measure 2 = var _table=SUMMARIZE('Table','Table'[Shop],'Table'[Date],"distinctcount",DISTINCTCOUNT('Table'[Customer]))
return
SUMX(_table,[distinctcount])

Result:

3.JPG

Regards,

Lin

 

 

Community Support Team _ Lin
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Anonymous
Not applicable

Hello @v-lili6-msft,

 

To go further, is it possible to calculate an average of this measure. A weekly average taking into account the working days

 

thank you

Anonymous
Not applicable

Thanks Lin. Sorry for the delay in response. Your formula worked.

ryan_mayu
Super User
Super User

@Anonymous 

 

Hi, why distinctcount formula doesnot work in this situation? Have you tried about that? Or you have some specific requirement?

screenshot1.JPGscreenshot2.JPG

Hope this is helpful.

 

Thanks and BR

Ryan





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parry2k
Super User
Super User

@Anonymous can you provide sample data and will get you the solution



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