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mikelee1701
Helper III
Helper III

Changing an aggregate on a column depending on a filter

Hi,

 

My data table is something like this:

 

Datetypevalue
8-3-2022average10
8-5-2022sum4
8-6-2022average6
8-7-2022sum4

 

I have a slicer on type where you can choose between average and sum

 

in my visual, when I filter by average I'd like my visual to show 8

when I filter by sum, i'd like my visual to show 8

 

but what I can't figure out is, in the visuals, I am limited by only choosing one aggregate.   Can I get around this?

 

Screenshot_090622_073844_PM.jpg

 

Thanks in advance.

Mike

1 ACCEPTED SOLUTION
mikelee1701
Helper III
Helper III

I guess it helps to take a break and come back:

I figured out how to do it.

I created a measure:

Mod-Value = SWITCH(max(table[type]),
"average", AVERAGE(AvailResp[Value]),
"sum", SUM(AvailResp[Value])
)

 

 

PS. Looking back at my question, I poorly choose my numbers where the end result is the same answer; which may cause confusion.

 

I should have choose numbers such sum of 50 and 50, is 100

and average of 10 and 6, is 8

 

regardless, I figured it out, and it appears to be working., thanks for reading.

 

 

View solution in original post

3 REPLIES 3
mikelee1701
Helper III
Helper III

I guess it helps to take a break and come back:

I figured out how to do it.

I created a measure:

Mod-Value = SWITCH(max(table[type]),
"average", AVERAGE(AvailResp[Value]),
"sum", SUM(AvailResp[Value])
)

 

 

PS. Looking back at my question, I poorly choose my numbers where the end result is the same answer; which may cause confusion.

 

I should have choose numbers such sum of 50 and 50, is 100

and average of 10 and 6, is 8

 

regardless, I figured it out, and it appears to be working., thanks for reading.

 

 

ryan_mayu
Super User
Super User

@mikelee1701 

should average be 16 or 13?

pls check the attachment to see if this is what you want.

1.PNG





Did I answer your question? Mark my post as a solution!

Proud to be a Super User!




Average should be 8.   (10+6 = 16, 16/2=8)

 

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