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I have two tables
Date table: Date
Product Table: product ID, Timestamp
The tables have an 1:M relation with cross filtering set to "both"
I have a slicer in a tab and I want to get the date difference between those two tabs. But I am getting wrong values because of my cross filtering criteria. I have tried DAX but I am unable to get the correct answer here.
If I try Dax to get Max date and Min date, it shows max date as 2020 and Min date as 2000. It does not give me the max and min dates of that slicer, Any help would be greatly appreciated here.
Days Measured=CALCULATE(COUNTROWS(CalendarDate),ALLSELECTED()) testmaxdate = CALCULATE(MAX(CalendarDate[CalendarDate].[Date]),ALLSELECTED(CalendarDate))
Solved! Go to Solution.
Hi @mady90 ,
You can create measures to get Max date and Min date of date slicer, as well the date difference , like DAX below:
Max date = CALCULATE(MIN(CalendarDate[Date]),ALLSELECTED(CalendarDate[Date])) Min date = CALCULATE(MAX(CalendarDate[Date]),ALLSELECTED(CalendarDate[Date])) DateDiff= DATEDIFF([Min date], [Max date], DAY)
If I misunderstood it, could you please share your sample data and desired output screenshots for further analysis? You can also upload sample pbix to OneDrive and post the link here. Do mask sensitive data before uploading.
Best Regards,
Amy
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @mady90 ,
You can create measures to get Max date and Min date of date slicer, as well the date difference , like DAX below:
Max date = CALCULATE(MIN(CalendarDate[Date]),ALLSELECTED(CalendarDate[Date])) Min date = CALCULATE(MAX(CalendarDate[Date]),ALLSELECTED(CalendarDate[Date])) DateDiff= DATEDIFF([Min date], [Max date], DAY)
If I misunderstood it, could you please share your sample data and desired output screenshots for further analysis? You can also upload sample pbix to OneDrive and post the link here. Do mask sensitive data before uploading.
Best Regards,
Amy
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
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