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FrontierGroup
Regular Visitor

Calculated column looking up previous value

Hi

 

I have the following data

 

Data Set.jpg

 

I would like to create a column subtracting the previous value, so I get a usage per line

 

Data Result.jpg

Appreciate any help

 

Thanks

 

Steve

1 ACCEPTED SOLUTION
Anonymous
Not applicable

Hi @FrontierGroup ,

 

follow these steps.

 

1. Add the Index column like this.

(Edit queries-->Add column--> Index Column--> from 1)

Capture122.PNG

 

2. You will get the Output something like this: (close and Apply after these steps)

Capture32.PNG

3. Now add this calculated Column like this and add the formula:

Capture22.PNG

Difference = 
 var curIndex = 'Table'[Index]
  var curCI = 'Table'[CI]
  var OLDIndex = 'Table'[Index]-1
  var oldVal = CALCULATE(
    FIRSTNONBLANK('Table'[CI],1),
    FILTER('Table', 
    'Table'[Index]=OLDIndex))
  return IF(CONTAINS('Table','Table'[Index],OLDIndex), curCI-oldVal, 0)

My output based on your sample:

Capture23.PNG

Let me know if this works.

 

Thanks,

Tejaswi

View solution in original post

2 REPLIES 2
Anonymous
Not applicable

Hi @FrontierGroup ,

 

follow these steps.

 

1. Add the Index column like this.

(Edit queries-->Add column--> Index Column--> from 1)

Capture122.PNG

 

2. You will get the Output something like this: (close and Apply after these steps)

Capture32.PNG

3. Now add this calculated Column like this and add the formula:

Capture22.PNG

Difference = 
 var curIndex = 'Table'[Index]
  var curCI = 'Table'[CI]
  var OLDIndex = 'Table'[Index]-1
  var oldVal = CALCULATE(
    FIRSTNONBLANK('Table'[CI],1),
    FILTER('Table', 
    'Table'[Index]=OLDIndex))
  return IF(CONTAINS('Table','Table'[Index],OLDIndex), curCI-oldVal, 0)

My output based on your sample:

Capture23.PNG

Let me know if this works.

 

Thanks,

Tejaswi

Hi Tejaswi

 

Thank you for your quick response and the solution you detailed works perfectly!

 

Thanks for your help

Steve

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