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I have two tables, where I am trying to make the right CalculatedColumn in table 2:
Table 1:
Id | Difference |
1 | 1 |
1 | 1 |
2 | 1 |
2 | 1 |
3 | 2 |
3 | 2 |
Table 2 (DESIRED OUTPUT TABLE)
Numbers | CalculatedColumn |
1 | 2 |
2 | 1 |
3 | 0 |
I need the right code for my "CalculatedColumn" in table 2.
The goal is to count the DISTINCT "Difference" value from table 1 for EACH Id, and add these together.
- So, you can see in table 1, both ID 1 & ID 2 have the distinct value of 1 EACH.
- 1+1 = 2, therefore the calculated column should put 2 as value where "Numbers" column = 1.
My attempt:
Counter =
SWITCH (
TRUE(),
Table2[Numbers] = 1, CALCULATE(SUM(Table1[Difference]),Table1[Difference] = 1),
Table2[Numbers] = 2, CALCULATE(SUM(Table1[Difference]),Table1[Difference] = 2
)
.. and so on.
Solved! Go to Solution.
Hi @msuser48 ,
Please follow these steps:
(1) Create a new column
Counter =
SWITCH (
TRUE(),
'Table 2'[Number] = 1, CALCULATE(DISTINCTCOUNT('Table 1' [ID]),'Table 1' [Difference] = 1),
'Table 2'[Number] = 2, CALCULATE(DISTINCTCOUNT('Table 1' [ID]),'Table 1' [Difference] = 2),
'Table 2'[Number] = 3, CALCULATE(DISTINCTCOUNT('Table 1' [ID]),'Table 1' [Difference] = 3)
)
(2)Final output
Best Regards,
Gallen Luo
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @msuser48 ,
Please follow these steps:
(1) Create a new column
Counter =
SWITCH (
TRUE(),
'Table 2'[Number] = 1, CALCULATE(DISTINCTCOUNT('Table 1' [ID]),'Table 1' [Difference] = 1),
'Table 2'[Number] = 2, CALCULATE(DISTINCTCOUNT('Table 1' [ID]),'Table 1' [Difference] = 2),
'Table 2'[Number] = 3, CALCULATE(DISTINCTCOUNT('Table 1' [ID]),'Table 1' [Difference] = 3)
)
(2)Final output
Best Regards,
Gallen Luo
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
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