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SAU1111
Frequent Visitor

Average Time between Repair Work orders

Hello All,

 

I have a table where cloumn1 = Porduct Name , Cloumn 2 = Serial Numbers of products , Cloumn 3 = Repair Work Order Numbers , Cloumn 4 = Work order Created date , Column 5 = Repair Work Order Closed Date . Now i have to find a time difference between last closed repair Work order date w.r.t previous repair closed date . Please suggest 

1 ACCEPTED SOLUTION

Hi @SAU1111 ,

If the Repair Work Order Numbers is random like below:

vkalyjmsft_0-1657592508991.png

You can create a column to rank the Closed Date for each Product Name and Serial Numbers of products, like this:

Rank =
RANKX (
    FILTER (
        'Table',
        'Table'[Porduct Name] = EARLIER ( 'Table'[Porduct Name] )
            && 'Table'[Serial Numbers of products]
                = EARLIER ( 'Table'[Serial Numbers of products] )
    ),
    'Table'[Repair Work Order Closed Date],
    ,
    ASC,
    DENSE
)

vkalyjmsft_1-1657592777416.png

Then create a measure.

Average Diff =
VAR _T =
    ADDCOLUMNS (
        'Table',
        "Diff",
            DATEDIFF (
                MAXX (
                    FILTER (
                        'Table',
                        'Table'[Rank]
                            = EARLIER ( 'Table'[Rank] ) - 1
                            && 'Table'[Porduct Name] = EARLIER ( 'Table'[Porduct Name] )
                            && 'Table'[Serial Numbers of products]
                                = EARLIER ( 'Table'[Serial Numbers of products] )
                    ),
                    'Table'[Repair Work Order Closed Date]
                ),
                'Table'[Repair Work Order Closed Date],
                DAY
            )
    )
RETURN
    AVERAGEX ( _T, [Diff] )

Get the result for each Product Name and Serial Numbers of products.

vkalyjmsft_2-1657592868772.png

I attach my sample below for reference.

 

Best Regards,
Community Support Team _ kalyj

If this post helps, then please considerAccept it as the solution to help the other members find it more quickly.

 

View solution in original post

3 REPLIES 3
SAU1111
Frequent Visitor

Sorry I forgot to mention that for 1 Serial numbers there can be N numbers of Work orders and there closed On date . Now problem is that more than 1 serial numbers has same repair work order closed on date . SO WOrk order numbers also be random cannot be arranged as on same day two Work order of a sequence like 1 and 2 can be for different serial numbers . Now First how to arrange by Serial Numbers all the WO and its closed on Date so that i can arrange the dates in ascending order and calculate a difference . 

Hi @SAU1111 ,

If the Repair Work Order Numbers is random like below:

vkalyjmsft_0-1657592508991.png

You can create a column to rank the Closed Date for each Product Name and Serial Numbers of products, like this:

Rank =
RANKX (
    FILTER (
        'Table',
        'Table'[Porduct Name] = EARLIER ( 'Table'[Porduct Name] )
            && 'Table'[Serial Numbers of products]
                = EARLIER ( 'Table'[Serial Numbers of products] )
    ),
    'Table'[Repair Work Order Closed Date],
    ,
    ASC,
    DENSE
)

vkalyjmsft_1-1657592777416.png

Then create a measure.

Average Diff =
VAR _T =
    ADDCOLUMNS (
        'Table',
        "Diff",
            DATEDIFF (
                MAXX (
                    FILTER (
                        'Table',
                        'Table'[Rank]
                            = EARLIER ( 'Table'[Rank] ) - 1
                            && 'Table'[Porduct Name] = EARLIER ( 'Table'[Porduct Name] )
                            && 'Table'[Serial Numbers of products]
                                = EARLIER ( 'Table'[Serial Numbers of products] )
                    ),
                    'Table'[Repair Work Order Closed Date]
                ),
                'Table'[Repair Work Order Closed Date],
                DAY
            )
    )
RETURN
    AVERAGEX ( _T, [Diff] )

Get the result for each Product Name and Serial Numbers of products.

vkalyjmsft_2-1657592868772.png

I attach my sample below for reference.

 

Best Regards,
Community Support Team _ kalyj

If this post helps, then please considerAccept it as the solution to help the other members find it more quickly.

 

v-yanjiang-msft
Community Support
Community Support

Hi @SAU1111 ,

According to your descrption, I create a sample.

vkalyjmsft_0-1657534908219.png

Here's my solution, create a measure.

Average Diff =
VAR _T =
    ADDCOLUMNS (
        'Table',
        "Diff",
            DATEDIFF (
                MAXX (
                    FILTER (
                        'Table',
                        'Table'[Repair Work Order Numbers]
                            = EARLIER ( 'Table'[Repair Work Order Numbers] ) - 1
                            && 'Table'[Porduct Name] = EARLIER ( 'Table'[Porduct Name] )
                            && 'Table'[Serial Numbers of products]
                                = EARLIER ( 'Table'[Serial Numbers of products] )
                    ),
                    'Table'[Repair Work Order Closed Date]
                ),
                'Table'[Repair Work Order Closed Date],
                DAY
            )
    )
RETURN
    AVERAGEX ( _T, [Diff] )

Get the correct result.

vkalyjmsft_1-1657534995788.png

I attach my sample below for reference.

 

Best Regards,
Community Support Team _ kalyj

If this post helps, then please considerAccept it as the solution to help the other members find it more quickly.

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