sum by rank and cpms

[reibalboaOMG]

Hi everyone can somebody help me?

here is my sample data 

in my  powerbi it already have a ranking 

i need a formula that sum of all cpm by social platform and ranking, on the right screenshot the output will be 8872

[reibalboaOMG · Accepted solution]

hi @FreemanZ,

i've filtered the social platform by FB and (all cost/post / all impression) * 1000
total computation of cost/post = 745,200

total computation of impression = 83,994

over all computation (cost:745,200/impression:83,994)*1000 = 8872 

my ranking is base on week of update 01/22 = 1, 01/29 = 2

rank 1 on FB will be 8872

mine has the wrong output because i could'n figure out the right formula for this

[reibalboaOMG]

hi @tamerj1 and @FreemanZ  i have a new problem that i encountered

focus yourself to COST EFFICIENCIES

youtube cpm has 5.97k on the first week

on the second week it has 3.70k which has the right color but if the value did'nt move on the next week it should be red.

cpmvalue = IF('Template (2)'[Postimpcpm] & MAX('Template (2)'[weekrank]) <= 'Template (2)'[Postimpcpm] & MIN('Template (2)'[weekrank]), "#CC6478", "#56AA93"

here is my field value formula^

[reibalboaOMG · Accepted solution]

hi @FreemanZ,

i've filtered the social platform by FB and (all cost/post / all impression) * 1000
total computation of cost/post = 745,200

total computation of impression = 83,994

over all computation (cost:745,200/impression:83,994)*1000 = 8872 

my ranking is base on week of update 01/22 = 1, 01/29 = 2

rank 1 on FB will be 8872

mine has the wrong output because i could'n figure out the right formula for this

[tamerj1 · Accepted solution]

@reibalboaOMG 
Not sure what could go wrong. Even a simple DIVDE/SUM shall do the job unless your data model is more complex that just a single table. In case of mutiple periods or platforms selected you may use the following to obtain correct aggregation.

=
SUMX (
    SUMMARIZE ( 'Table', 'Table'[Social Platform], 'Table'[Rank] ),
    CALCULATE (
        DIVIDE ( SUM ( 'Table'[Cost/Post] ), SUM ( 'Table'[Post Impression] ) ) * 1000
    )
)

[FreemanZ]

hi @reibalboaOMG 

not quite sure how do you get  8872, could you elaborate that?