rolling mtd of working days with slicer selection

[adrianPadurariu]

Hello,

I am trying to have a measure that calculates the rolling sum of working days from the beginning of the month until the selected working day.

I have a Date table where I created:

weekday = WEEKDAY('Calendar'[Date],2)

Then I created the number of working days in the month:

# working days = IF( TOTALMTD(SUM('Calendar'[workday]),'Calendar'[Date]) = 0 , 1 , TOTALMTD(SUM('Calendar'[workday]),'Calendar'[Date]))

Fact table with the column TotalFacialValue

One slicer with Year/Month

One Slicer with # working days

I need to calculate rolling MTD from the begining of the selected Year/Month, until the selected # working days

Example: If I will select # of working numbers = 10 with January/2022, the measure will calculate from 3rd of January( the first working day in the month), until 14th of January (the 10th working day)

[Anonymous · Accepted solution]

Hi @adrianPadurariu ,

According to your description, here are my steps you can follow as a solution.

(1) This is my test data. 

(2) We can create a table. Use the column of the new table as slicer.

SlicerTable = GENERATESERIES(1,35,1)

(3)We can create a measure.

Measure = 
var _a=CALCULATE(SUM('Fact table'[TotalFacialValue]),FILTER(ALLSELECTED('Calendar'),[# working days]<= SELECTEDVALUE('SlicerTable'[slicer working day]) && [# working days]=1 && 'Calendar'[WorkDay]<>0))
var _b=CALCULATE(SUM('Fact table'[TotalFacialValue]),FILTER(ALLSELECTED('Calendar'),[# working days]<= SELECTEDVALUE('SlicerTable'[slicer working day]) && [# working days]<>1 && [# working days]<>0))
return IF([# working days]=SELECTEDVALUE('SlicerTable'[slicer working day]),_a+_b,BLANK())

(4) Then the result is as follows.

If the above one can't help you get the desired result, please provide some sample data in your tables (exclude sensitive data) with Text format and your expected result with backend logic and special examples. It is better if you can share a simplified pbix file. Thank you.

Best Regards,

Neeko Tang

If this post  helps, then please consider Accept it as the solution  to help the other members find it more quickly. 

[adrianPadurariu]

Thank you, it's working.