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Anonymous
Not applicable

SUM Range divided by Sum Range last 6 rows

Hi Guys,

 

What I would like to get is, each new month to show :

Range of last 6 month (Sale)  / Range of last 6 month (Shop 1 - Categories). 

Anyone could help please ?

sonicmaster_0-1649160940628.png

 

 

MonthSaleShop 1 - Categories
Jan12004
Feb13002
Mar8005
Apr5004
May6004
Jun1505
Jul12005 
   
1 ACCEPTED SOLUTION

Hi, @Anonymous 

Please try measure formulas as below:

Measure1 =
SUMX (
    TOPN (
        6,
        FILTER ( ALL ( 'Table' ), 'Table'[ID] <= MAX ( 'Table'[ID] ) ),
        'Table'[ID], DESC
    ),
    'Table'[Sale]
)
Measure2 =
SUMX (
    TOPN (
        6,
        FILTER ( ALL ( 'Table' ), 'Table'[ID] <= MAX ( 'Table'[ID] ) ),
        'Table'[ID], DESC
    ),
    'Table'[Shop 1 - Categories]
)
Result = [Measure1]/[Measure2]

1.png

Best Regards,
Community Support Team _ Eason
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

2 REPLIES 2
Anonymous
Not applicable

OK I managed to get a bit forward with that :

I added ID column 1 2 3 4 ect.

 

My meaurement =
DIVIDE(SUMx(TOPN(6,'Table','Table'[ID],DESC),'Table'[Sale]),SUMx(TOPN(6,'Table','Table'[ID],DESC),'Table'[Shop 1 - Categories]),0)
 
So card can show values I want  in connection with column chart ( each time I select another month it all adds up) ,but how to set my results  416,300,253,231,189 on Line chart ? 
 
Please help ?
 
 
sonicmaster_0-1649322447868.png

 

Hi, @Anonymous 

Please try measure formulas as below:

Measure1 =
SUMX (
    TOPN (
        6,
        FILTER ( ALL ( 'Table' ), 'Table'[ID] <= MAX ( 'Table'[ID] ) ),
        'Table'[ID], DESC
    ),
    'Table'[Sale]
)
Measure2 =
SUMX (
    TOPN (
        6,
        FILTER ( ALL ( 'Table' ), 'Table'[ID] <= MAX ( 'Table'[ID] ) ),
        'Table'[ID], DESC
    ),
    'Table'[Shop 1 - Categories]
)
Result = [Measure1]/[Measure2]

1.png

Best Regards,
Community Support Team _ Eason
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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