Left outer join in DAX on Dimesnion and Fact

[abhiram342]

Hi all,

I have Fact and Dimension Table. I'm querying the cube using DAX code. I want to get all the values from dimension table irrespective they have value in Fact. Currenlty because 1 ( dimension) to many (fact) relationship between dimesnon and fact, I'm getting less records

EX:

Dimension

ProductID	ProductName
1	Cycle
2	Car

Fact

Date	ProductId	Amount
2021-12-20	1	2

final Result

ProductID	ProductName	Amount
1	Cycle	2
2	bike

DAX Code: EVALUATE

SELECTCOLUMNS(

SUMMARIZE(

ProductId,ProductName,"TotalAmount",'Amount')

ProductId,

ProductName,

"TotalAmount","TotalAmount")

Thanks,

Abhiram

[v-kkf-msft · Accepted solution]

Hi @abhiram342 ,

Since you have a 1:* relationship between the Fact table and Dimension table, then to achieve a left outer join, you need to enable the option "Show items with no data" only.

If the problem is still not resolved, please provide detailed error information or the expected result you expect. Let me know immediately, looking forward to your reply.

Best Regards,
Winniz

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[abhiram342]

Hi Vahid - Sorry , It's typo final result as below. Relationship betwen dimension and table is Star Schema 1 to many

ProductId	ProductName	Amount
1	Cycle	2
2	Car

[VahidDM]

Hi @abhiram342 

Can you please let us know the relationship between those Fact and dimension tables? which columns and the cardinality?

Then how did you add Bike to the final result table?

Appreciate your Kudos!!
LinkedIn: www.linkedin.com/in/vahid-dm/

[abhiram342]

Hi @VahidDM  - Sorry , It's typo, final result as below. Relationship betwen dimension and table is Star Schema 1 to many

ProductId	ProductName	Amount
1	Cycle	2
2	Car

[VahidDM]

Hi @abhiram342 

use this code to create a new table:

Table = 
ADDCOLUMNS (
    'Dimension',
    "Amount",
        CALCULATE (
            SUM ( 'Fact'[Amount] ),
            FILTER ( 'Fact', 'Fact'[ProductId] = EARLIER ( 'Dimension'[ProductID] ) )
        )
)

Output:

If this post helps, please consider accepting it as the solution to help the other members find it more quickly.
Appreciate your Kudos!!
LinkedIn: www.linkedin.com/in/vahid-dm/