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Anonymous
Not applicable

How to get a specific date

I have a column I need to filter. As of Now I have it like this:

 

BeforeToday_MI = IF(Query_Util[MoveInDate].[Date] < TODAY(), True, False) 
 
It returns True if MoveInDate column has dates prior to today. However, I want the function to return true if the date is before Today AND the day is not Saturday or Sunday; in other words, the date belong to a weekday and not a weekend.

 

I tried this but it's giving me error: 

BeforeToday_MI = IF(Query_Util[MoveInDate].[Date] < TODAY() && VALUE(Query_Util[MoveInDate].[Day]) <> "Saturday", True, False)
1 ACCEPTED SOLUTION
amitchandak
Super User
Super User

@Anonymous ,

 

BeforeToday_MI = IF( datevalues(Query_Util[MoveInDate]) < TODAY() && weekday(Query_Util[MoveInDate],2) <6 , True, False) 

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3 REPLIES 3
amitchandak
Super User
Super User

@Anonymous ,

 

BeforeToday_MI = IF( datevalues(Query_Util[MoveInDate]) < TODAY() && weekday(Query_Util[MoveInDate],2) <6 , True, False) 

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Anonymous
Not applicable

What if I want to get the days that are not Saturday or Sunday?

 

(My bad; I forgot to include that specification before. I need work days. Your code works perfectly; I just need to act the condition of filtering out Sunday as well.)

Hi @Anonymous ,

 

Did you get your problem solved? If it was solved, please mark it as a solution so that more people can find it. If not, refer to the following.

 

weekday(Query_Util[MoveInDate],2) return result follow the following rule.

week begins on Monday (1) and ends on Sunday (7).

 

If you only want filter out  sunday, then weekday(Query_Util[MoveInDate],2) <7. Or enter the day you want like this:

weekday(Query_Util[MoveInDate],2) = 1 &&

weekday(Query_Util[MoveInDate],2) = 2 &&

weekday(Query_Util[MoveInDate],2) = 3 &&

weekday(Query_Util[MoveInDate],2) = 4

 

More detail you can refer this function.

WEEKDAY function (DAX) - DAX | Microsoft Docs

 

Best Regards

Community Support Team _ chenwu zhu

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

 

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