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Anonymous
Not applicable

How to calculate the % of the most common value in a column

Hi there,

 

I have a column called [result_value] that has multiple rows, for example, the most common row is "Art & Design" there are 12 rows with that specific value, I want a % calculated from that.

 

It looks quite simple but I haven't found a way to do it surprisingly. I want to see the total % of the top value in comparison to the rest of the entries, not just specifically "Art & Design", as there might be other values in future that surpass it.

1 ACCEPTED SOLUTION
tamerj1
Super User
Super User

Hi @Anonymous 
This should work in a cadr visual 

 

Most Common % =
VAR CountAll =
    COUNTROWS ( TableName )
VAR ValuesFrequency =
    ADDCOLUMNS (
        TableName,
        "@Frequency",
            COUNTROWS (
                CALCULATETABLE ( TableName, ALLEXCEPT ( TableName, TableName[result_value] ) )
            )
    )
VAR MaxFrequency =
    MAXX ( ValuesFrequency, [@Frequency] )
RETURN
    DIVIDE ( MaxFrequency, CountAll )

 

View solution in original post

5 REPLIES 5
tamerj1
Super User
Super User

Hi @Anonymous 
This should work in a cadr visual 

 

Most Common % =
VAR CountAll =
    COUNTROWS ( TableName )
VAR ValuesFrequency =
    ADDCOLUMNS (
        TableName,
        "@Frequency",
            COUNTROWS (
                CALCULATETABLE ( TableName, ALLEXCEPT ( TableName, TableName[result_value] ) )
            )
    )
VAR MaxFrequency =
    MAXX ( ValuesFrequency, [@Frequency] )
RETURN
    DIVIDE ( MaxFrequency, CountAll )

 

Anonymous
Not applicable

Hi @tamerj1 

Thanks for the response, I'm not sure why but I'm getting this error when I apply it 

KA95_0-1654441231612.png

 

@Anonymous 

The last part use CountAll not the table name

Anonymous
Not applicable

Apologies @tamerj1 I'm not sure why I did that... I must have read it wrong, anyway it works now greatly appreciate it. 

@Anonymous 
Please do not apologies. It was actually my mistake. Please accept my appology and thank you for marking my reply as acceptable solution.

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