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Anonymous's avatar
Anonymous
Not applicable
4 years ago
Solved

Help with DAX

Hi,

I just have started with DAX, and I would create my first measure, but something is wrong.

I have a comment "cannot find name of column".

Could you explain to me why is that?

 

 

  • If you're writing a measure, then you can't refer to a raw column since it doesn't know which values from that column you want are, so you need to use some kind of aggregation.

     

    Assuming there actually is a column named STATUS in the table 'EWW 2022', you can write

    IF (
        SELECTEDVALUE ( 'EWW 2022'[STATUS] ) = "REALIZACJA",
        SUM ( 'EWW 2022'[TURNOVER] )
    )

     

    However, the error message associated with the common DAX mistake above is different.

     

    Are you sure STATUS is actually a column on 'EWW 2022' and not a different table and that there aren't extra spaces or something similar in the name?

4 Replies

  • If you're writing a measure, then you can't refer to a raw column since it doesn't know which values from that column you want are, so you need to use some kind of aggregation.

     

    Assuming there actually is a column named STATUS in the table 'EWW 2022', you can write

    IF (
        SELECTEDVALUE ( 'EWW 2022'[STATUS] ) = "REALIZACJA",
        SUM ( 'EWW 2022'[TURNOVER] )
    )

     

    However, the error message associated with the common DAX mistake above is different.

     

    Are you sure STATUS is actually a column on 'EWW 2022' and not a different table and that there aren't extra spaces or something similar in the name?

    • bcdobbs's avatar
      bcdobbs
      Community Champion

      Were you trying to sum the turnover column only where the status of each row equaled REALIZACJA?

       

      If so I think the following is what you want:

       

       

      CALCULATE(
          SUM ( 'EWW 2022'[TURNOVER] ),
          'EWW 2022'[STATUS] = "REALIZACJA"
      )

       

       


      CALCULATE lets you add a filter in directly (amoungst other things!) rather than relying on a slicer etc.

    • Anonymous's avatar
      Anonymous
      Not applicable

      Thank you so much for your help!
      It was exactly what I needed 🙂
      I wanted to start with a simple function, and it turned out that it isn't as easy as I thought