Get only one matching month and year of other date column

[newlearnpbi123]

I have two date column,

one column has month-year and another column is weekend-dates, like below image

i want to have only one matching month and year of the month column, like below

the issue is starting of month and end of month sometimes present in previous month as highlighted in first image,

can someone help me get the result of 2nd image, any date is fine as long it is only one date matching the month column, so i could use it in  my slicer.

[saurabhtd · Accepted solution]

@newlearnpbi123  You can create new column like

any date = DATE(YEAR('Calendar'[Month-Year]),MONTH('Calendar'[Month-Year]),1 )

Here we are creating new date column wheere year and month will ba taken from Year-Month column and Day will be 1. So they will be one date for each Month. You can keep Day as any other number between 0-28. 

[Anonymous · Accepted solution]

Hi @newlearnpbi123 ,

You can try this way:
Here is my sample date:

I use these DAXs below to create two new columns to extract year and month:

Year = YEAR('Table'[Date])

Month = MONTH('Table'[Date])

Then I use this DAX to create a new table to achieve your purpose:

Slicer = 
SUMMARIZE(
    'Table',
    'Table'[Year],
    'Table'[Month],
    "slicer",
    MIN('Table'[Date])
)

Best Regards,
Dino Tao
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[saurabhtd · Accepted solution]

@newlearnpbi123  You can create new column like

any date = DATE(YEAR('Calendar'[Month-Year]),MONTH('Calendar'[Month-Year]),1 )

Here we are creating new date column wheere year and month will ba taken from Year-Month column and Day will be 1. So they will be one date for each Month. You can keep Day as any other number between 0-28.