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Anonymous's avatar
Anonymous
Not applicable
4 years ago
Solved

Display Image IF

Hi,

 

I want to display an Image conditionally, but I have errors in my Syntax...

 

DisplayExclamation =
IF(
'FaktStruktur'[Attribute] = 'Basisinfo:KontroversenBeschreibung' && 'FaktStruktur'[Value] <> BLANK,
"https://www.dropbox.com/s/c2tcp28cyzg6pku/Ausrufezeichen-klein.png?raw=1"
)

 

Is it possible this way? DataCategory = ImageURL, so the display of the image itself is ok

  • AlexisOlson's avatar
    AlexisOlson
    4 years ago

    Try using double quotes around the attribute:

    DisplayExclamation =
IF (
    'FaktStruktur'[Attribute] = "Basisinfo:KontroversenBeschreibung"
        && 'FaktStruktur'[Value] <> BLANK,
    "https://www.dropbox.com/s/c2tcp28cyzg6pku/Ausrufezeichen-klein.png?raw=1"
)

1 Reply

  • AlexisOlson's avatar
    AlexisOlson
    Super User
    4 years ago

    Try using double quotes around the attribute:

    DisplayExclamation =
IF (
    'FaktStruktur'[Attribute] = "Basisinfo:KontroversenBeschreibung"
        && 'FaktStruktur'[Value] <> BLANK,
    "https://www.dropbox.com/s/c2tcp28cyzg6pku/Ausrufezeichen-klein.png?raw=1"
)