DISTINCTCOUNT

[wyanjaspew]

Hi Everyone,

Please help me on this. TA

[wyanjaspew · Accepted solution]

oh got it, doesn't applicable on creating table. thanks @FreemanZ!

[FreemanZ]

if you want the distinct list, try like:

DISTINCT(Table[Col])

or 

VALUES(Table[Col])

or

ALL(Table[Col])

[FreemanZ]

hi @wyanjaspew 

it seems you want a measure, but actually creating a calculated table. or?