wyanjaspewAdvocate I3 years agoSolvedDISTINCTCOUNT Hi Everyone, Please help me on this. TA Show Morewyanjaspew3 years agooh got it, doesn't applicable on creating table. thanks FreemanZ!
FreemanZSuper User to wyanjaspew3 years agoif you want the distinct list, try like:DISTINCT(Table[Col])or VALUES(Table[Col])orALL(Table[Col])
FreemanZSuper User to wyanjaspew3 years agoif you want the distinct list, try like:DISTINCT(Table[Col])or VALUES(Table[Col])orALL(Table[Col])
Related contentDISTINCTCOUNT with filtersDistinctCount IF?DISTINCTCOUNT with conditionDistinctcountalternative for DISTINCTCOUNT
