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My data set is in a table as shown below. KPI1 to KPI 6 are calculated columns.
Now I want to calculate the total number of Pass KPI in a column at the end for the combination of Type and Band.
The expected output table is also shown below.
Input table
| Area | Zone | Type | Band | KPI1(P/F) | KPI2(P/F) | KPI3(P/F) | KPI4(P/F) | KPI5(P/F) | KPI6(P/F) |
| BR | ARRH-0001 | PRE | 1 | Pass | Pass | Fail | Pass | Pass | Fail |
| BR | ARRH-0001 | PRE | 2 | Pass | Fail | Fail | Pass | Pass | Fail |
| BR | ARRH-0002 | POST | 2 | Pass | Pass | Pass | Pass | Pass | Pass |
| BR | ARRH-0002 | PRE | 2 | Pass | Fail | Pass | Pass | Pass | Fail |
| BR | ARRH-0002 | PRE | 1 | Pass | Pass | Pass | Pass | Pass | Fail |
| BR | BGLP-0003 | PRE | 2 | Pass | Fail | Pass | Pass | Pass | Fail |
| BR | BGLP-0003 | PRE | 1 | Pass | Pass | Pass | Pass | Pass | Pass |
| BR | BGLP-0004 | PRE | 2 | Pass | Pass | Pass | Pass | Pass | Fail |
| BR | BGLP-0004 | PRE | 1 | Pass | Pass | Pass | Pass | Pass | Fail |
Expected output table
| Area | Zone | Type | Band | KPI1(P/F) | KPI2(P/F) | KPI3(P/F) | KPI4(P/F) | KPI5(P/F) | KPI6(P/F) | Pass KPI count |
| BR | ARRH-0001 | PRE | 1 | Pass | Pass | Fail | Pass | Pass | Fail | 4 |
| BR | ARRH-0001 | PRE | 2 | Pass | Fail | Fail | Pass | Pass | Fail | 3 |
| BR | ARRH-0002 | POST | 2 | Pass | Pass | Pass | Pass | Pass | Pass | 6 |
| BR | ARRH-0002 | PRE | 2 | Pass | Fail | Pass | Pass | Pass | Fail | 4 |
| BR | ARRH-0002 | PRE | 1 | Pass | Pass | Pass | Pass | Pass | Fail | 5 |
| BR | BGLP-0003 | PRE | 2 | Pass | Fail | Pass | Pass | Pass | Fail | 4 |
| BR | BGLP-0003 | PRE | 1 | Pass | Pass | Pass | Pass | Pass | Pass | 6 |
| BR | BGLP-0004 | PRE | 2 | Pass | Pass | Pass | Pass | Pass | Fail | 5 |
| BR | BGLP-0004 | PRE | 1 | Pass | Pass | Pass | Pass | Pass | Fail | 5 |
Solved! Go to Solution.
Hi @prashantg364 ,
Please try this.
Count of Pass measure =
var _KPI1 =MAX(PassTable[KPI1(P/F)])
var _KPI2=MAX(PassTable[KPI2(P/F)])
var _KPI3 =MAX(PassTable[KPI3(P/F)])
var _KPI4 =MAX(PassTable[KPI4(P/F)])
var _KPI5 =MAX(PassTable[KPI5(P/F)])
var _KPI6 =MAX(PassTable[KPI6(P/F)])
var _calc = IF(_KPI1= "Pass", 1,0) + IF(_KPI2= "Pass", 1,0) + IF(_KPI3= "Pass", 1,0) + IF(_KPI4= "Pass", 1,0) + IF(_KPI5= "Pass", 1,0) + IF(_KPI6= "Pass", 1,0)
return
_calc
Let me know if you have any questions.
If this solves your issues, please mark it as the solution, so that others can find it easily. Kudos 👍are nice too.
Nathaniel
Proud to be a Super User!
@prashantg364
Other approches
KPI count 1 =
SUMX (
'Table',
INT ( 'Table'[KPI1(P/F)] = "Pass" ) + INT ( 'Table'[KPI2(P/F)] = "Pass" )
+ INT ( 'Table'[KPI3(P/F)] = "Pass" ) + INT ( 'Table'[KPI4(P/F)] = "Pass" )
+ INT ( 'Table'[KPI5(P/F)] = "Pass" ) + INT ( 'Table'[KPI6(P/F)] = "Pass" )
)KPI count 2 =
COUNTROWS (
FILTER (
SELECTCOLUMNS (
GENERATE (
GENERATESERIES ( 1, 6, 1 ),
'Table'
),
"KPI",
SWITCH (
[Value],
1, 'Table'[KPI1(P/F)], 2, 'Table'[KPI2(P/F)], 3, 'Table'[KPI3(P/F)],
4, 'Table'[KPI4(P/F)], 5, 'Table'[KPI5(P/F)], 6, 'Table'[KPI6(P/F)]
)
),
[KPI] = "Pass"
)
)
Hi @prashantg364 ,
Please try this.
Count of Pass measure =
var _KPI1 =MAX(PassTable[KPI1(P/F)])
var _KPI2=MAX(PassTable[KPI2(P/F)])
var _KPI3 =MAX(PassTable[KPI3(P/F)])
var _KPI4 =MAX(PassTable[KPI4(P/F)])
var _KPI5 =MAX(PassTable[KPI5(P/F)])
var _KPI6 =MAX(PassTable[KPI6(P/F)])
var _calc = IF(_KPI1= "Pass", 1,0) + IF(_KPI2= "Pass", 1,0) + IF(_KPI3= "Pass", 1,0) + IF(_KPI4= "Pass", 1,0) + IF(_KPI5= "Pass", 1,0) + IF(_KPI6= "Pass", 1,0)
return
_calc
Let me know if you have any questions.
If this solves your issues, please mark it as the solution, so that others can find it easily. Kudos 👍are nice too.
Nathaniel
Proud to be a Super User!
Hi @prashantg364 ,
If You need a calculated column instead
Count of Pass col = IF([KPI1(P/F)]= "Pass", 1,0) + IF([KPI2(P/F)]= "Pass", 1,0) + IF([KPI3(P/F)] ="Pass", 1,0) + IF([KPI4(P/F)]= "Pass", 1,0) + IF([KPI5(P/F)]= "Pass", 1,0) + IF([KPI6(P/F)]="Pass", 1,0)
However, best use, most times, is using a measure.
Let me know if you have any questions.
If this solves your issues, please mark it as the solution, so that others can find it easily. Kudos 👍are nice too.
Nathaniel
Proud to be a Super User!
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