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EAPCGF
Frequent Visitor

DAX for percent of stacked column (only column not GT) with date hierarchy

I have a stacked column chart with two categories in the series/legend (under 65 and over 65). It shows a count of people in each of the two series.

I also have a date heirarchy on the x axis.

I need the series to display data labels showing count AND percent of total for each column (not percent of grand total). 

I have created a measure using DAX to calculate the percent of total and added this to the detail section of the data labels. This works well for a single stacked column, but when I add the date heirarchy it shows percent of grand total, not percent of each column.

What DAX can I use to get percent of series in each column? ie numerator - series, denominator total for both series in that month/quarter/year.
or is there another way to do this?

Thanks

 

Percent Stream2 =
DIVIDE(
    DISTINCTCOUNT(Table1[ID] ),
    CALCULATE(
        DISTINCTCOUNT(Table1[ID] ),
        ALLSELECTED()
    )
)

DAX Q.png

2 ACCEPTED SOLUTIONS
DataInsights
Super User
Super User

@EAPCGF,

 

This solution assumes that your model has a date table (best practice). The concept is to keep the Month filter context while clearing all other filters originating within the visual.

 

Percent Stream2 =
DIVIDE (
    DISTINCTCOUNT ( Table1[ID] ),
    CALCULATE (
        DISTINCTCOUNT ( Table1[ID] ),
        ALLSELECTED (),
        VALUES ( 'Date'[Month] )
    )
)

 





Did I answer your question? Mark my post as a solution!

Proud to be a Super User!




View solution in original post

Perfect! Thank you 🙂

View solution in original post

2 REPLIES 2
DataInsights
Super User
Super User

@EAPCGF,

 

This solution assumes that your model has a date table (best practice). The concept is to keep the Month filter context while clearing all other filters originating within the visual.

 

Percent Stream2 =
DIVIDE (
    DISTINCTCOUNT ( Table1[ID] ),
    CALCULATE (
        DISTINCTCOUNT ( Table1[ID] ),
        ALLSELECTED (),
        VALUES ( 'Date'[Month] )
    )
)

 





Did I answer your question? Mark my post as a solution!

Proud to be a Super User!




Perfect! Thank you 🙂

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