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rdnguyen's avatar
rdnguyen
Helper V
3 years ago
Solved

Count distinct with priority

Hi everyone, I have a list of items that I did count for late delivery and on time delivery. It means the item could be in both category Late and On-time. By doing the count for each category, I re...
  • v-jianboli-msft's avatar
    v-jianboli-msft
    3 years ago

    Hi rdnguyen ,

     

    Based on your description, I have created a simple sample:

    Please try:

    Late = 
var _a = SUMMARIZE('Table',[ID],"Flag",IF("Late" in SELECTCOLUMNS(FILTER(ALL('Table'),[ID]=EARLIER('Table'[ID])),"Category",[Category]),"Late","On-Time"))
return COUNTX(FILTER(_a,[Flag]="Late"),[Flag])

On-Time = 
var _a = SUMMARIZE('Table',[ID],"Flag",IF("Late" in SELECTCOLUMNS(FILTER(ALL('Table'),[ID]=EARLIER('Table'[ID])),"Category",[Category]),"Late","On-Time"))
return COUNTX(FILTER(_a,[Flag]="On-Time"),[Flag])

    Final output:

    Best Regards,

    Jianbo Li

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

v-jianboli-msft's avatar
v-jianboli-msft
Community Support
3 years ago

Hi rdnguyen ,

 

Based on your description, I have created a simple sample:

Please try:

Late = 
var _a = SUMMARIZE('Table',[ID],"Flag",IF("Late" in SELECTCOLUMNS(FILTER(ALL('Table'),[ID]=EARLIER('Table'[ID])),"Category",[Category]),"Late","On-Time"))
return COUNTX(FILTER(_a,[Flag]="Late"),[Flag])

On-Time = 
var _a = SUMMARIZE('Table',[ID],"Flag",IF("Late" in SELECTCOLUMNS(FILTER(ALL('Table'),[ID]=EARLIER('Table'[ID])),"Category",[Category]),"Late","On-Time"))
return COUNTX(FILTER(_a,[Flag]="On-Time"),[Flag])

Final output:

Best Regards,

Jianbo Li

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.