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mdgene's avatar
mdgene
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4 years ago
Solved

Using Column name as a variable

Hi Please I am trying to pass column name as a variable to create a table.   This query is fine (Ii am using the column name explicitly) TestTable = var b = CALCULATETABLE( SELECTCOLUMNS('Hou...
  • v-angzheng-msft's avatar
    4 years ago

    Hi, mdgene 

    Because in the following formula, the variable T is not recognized as a column in the table, but as a text. You cannot label a column in the variable way above.
    Therefore, in the filter function, the filtering condition is that text 1 is equal to text 2, not that the column value is equal to "b", so the result of the filter function is empty, and the returned table is empty.

     

     

    Best Regards,
    Community Support Team _ Zeon Zheng


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