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Syndicate_Admin
Administrator
Administrator

Obtener una dirección de BING MAP API usando latitud y longitud: se devuelven varias filas

Hola, uso esta función personalizada para obtener la dirección de mi latitud y longitud usando el mapa de la API de BING.

Pero en el resourceSet, obtengo muchos resultados.

¿Cómo puedo obtener solo lo más preciso?

Aquí está mi función:

let

    FindLoc= (lat, lon) =>

let
    Source = Xml.Tables(Web.Contents("http://dev.virtualearth.net/REST/v1/Locations/"&Text.From(lat)&"'" &Text.From(lon)&"?o=xml&key=AqXbM3RmYA05LA89D0jBdRSYxgrYNUOwSNEsDS2G9aXaYBqFDOIYDT8IPoHKhJRp")),
    #"Type modifié" = Table.TransformColumnTypes(Source,{{"Copyright", type text}, {"BrandLogoUri", type text}, {"StatusCode", Int64.Type}, {"StatusDescription", type text}, {"AuthenticationResultCode", type text}, {"TraceId", type text}}),
    #"ResourceSets développé" = Table.ExpandTableColumn(#"Type modifié", "ResourceSets", {"ResourceSet"}, {"ResourceSets.ResourceSet"}),
    #"ResourceSets ResourceSet" = #"ResourceSets développé"{0}[ResourceSets.ResourceSet],
    #"Type modifié1" = Table.TransformColumnTypes(#"ResourceSets ResourceSet",{{"EstimatedTotal", Int64.Type}}),
    Resources = #"Type modifié1"{0}[Resources],
    Location = Resources{0}[Location]  
in
    #"Location"

in
    FindLoc

Gracias por su ayuda,

Jérôme

1 ACCEPTED SOLUTION

Aquí está la solución:

let

    FindLoc= (lat, lon) =>

let
    Source = Xml.Tables(Web.Contents("http://dev.virtualearth.net/REST/v1/Locations/"&Replacer.ReplaceText(Text.From(lat),",",".")&","&Replacer.ReplaceText(Text.From(lon),",",".")&"?o=xml&key=AqXbM3RmYA05LA89D0jBdRSYxgrYNUOwSNEsDS2G9aXaYBqFDOIYDT8IPoHKhJRp")),
    #"Type modifié" = Table.TransformColumnTypes(Source,{{"Copyright", type text}, {"BrandLogoUri", type text}, {"StatusCode", Int64.Type}, {"StatusDescription", type text}, {"AuthenticationResultCode", type text}, {"TraceId", type text}}),
    #"ResourceSets développé" = Table.ExpandTableColumn(#"Type modifié", "ResourceSets", {"ResourceSet"}, {"ResourceSets.ResourceSet"}),
    #"ResourceSets ResourceSet" = #"ResourceSets développé"{0}[ResourceSets.ResourceSet],
    #"Type modifié1" = Table.TransformColumnTypes(#"ResourceSets ResourceSet",{{"EstimatedTotal", Int64.Type}}),
    Resources = #"Type modifié1"{0}[Resources],
    Location = Resources{0}[Location]  
in
    #"Location"

in
    FindLoc

View solution in original post

3 REPLIES 3
Syndicate_Admin
Administrator
Administrator

Hi, @jsteffe ;

Puede verificar si estas publicaciones relacionadas pueden ser útiles para usted.

Uso de la API de Mapas de Bing para devolver latitud y longitud en Power Query – Wise Data Decisions

API de ubicaciones: | de Bing Maps Microsoft Learn


Saludos
Equipo de Apoyo a la Comunidad _ Yalan Wu
Si esta publicación ayuda, considere Aceptarlo como la solución para ayudar a los otros miembros a encontrarlo más rápidamente.

Syndicate_Admin
Administrator
Administrator

Cuando escribo la URL directamente, uso una coma entre lat y lon, pero si escribo mi función así, no funciona:

Text.From(lat)&"," &Text.From(lon)

Aquí está la solución:

let

    FindLoc= (lat, lon) =>

let
    Source = Xml.Tables(Web.Contents("http://dev.virtualearth.net/REST/v1/Locations/"&Replacer.ReplaceText(Text.From(lat),",",".")&","&Replacer.ReplaceText(Text.From(lon),",",".")&"?o=xml&key=AqXbM3RmYA05LA89D0jBdRSYxgrYNUOwSNEsDS2G9aXaYBqFDOIYDT8IPoHKhJRp")),
    #"Type modifié" = Table.TransformColumnTypes(Source,{{"Copyright", type text}, {"BrandLogoUri", type text}, {"StatusCode", Int64.Type}, {"StatusDescription", type text}, {"AuthenticationResultCode", type text}, {"TraceId", type text}}),
    #"ResourceSets développé" = Table.ExpandTableColumn(#"Type modifié", "ResourceSets", {"ResourceSet"}, {"ResourceSets.ResourceSet"}),
    #"ResourceSets ResourceSet" = #"ResourceSets développé"{0}[ResourceSets.ResourceSet],
    #"Type modifié1" = Table.TransformColumnTypes(#"ResourceSets ResourceSet",{{"EstimatedTotal", Int64.Type}}),
    Resources = #"Type modifié1"{0}[Resources],
    Location = Resources{0}[Location]  
in
    #"Location"

in
    FindLoc

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