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Hola, uso esta función personalizada para obtener la dirección de mi latitud y longitud usando el mapa de la API de BING.
Pero en el resourceSet, obtengo muchos resultados.
¿Cómo puedo obtener solo lo más preciso?
Aquí está mi función:
let
FindLoc= (lat, lon) =>
let
Source = Xml.Tables(Web.Contents("http://dev.virtualearth.net/REST/v1/Locations/"&Text.From(lat)&"'" &Text.From(lon)&"?o=xml&key=AqXbM3RmYA05LA89D0jBdRSYxgrYNUOwSNEsDS2G9aXaYBqFDOIYDT8IPoHKhJRp")),
#"Type modifié" = Table.TransformColumnTypes(Source,{{"Copyright", type text}, {"BrandLogoUri", type text}, {"StatusCode", Int64.Type}, {"StatusDescription", type text}, {"AuthenticationResultCode", type text}, {"TraceId", type text}}),
#"ResourceSets développé" = Table.ExpandTableColumn(#"Type modifié", "ResourceSets", {"ResourceSet"}, {"ResourceSets.ResourceSet"}),
#"ResourceSets ResourceSet" = #"ResourceSets développé"{0}[ResourceSets.ResourceSet],
#"Type modifié1" = Table.TransformColumnTypes(#"ResourceSets ResourceSet",{{"EstimatedTotal", Int64.Type}}),
Resources = #"Type modifié1"{0}[Resources],
Location = Resources{0}[Location]
in
#"Location"
in
FindLoc
Gracias por su ayuda,
Jérôme
Solved! Go to Solution.
Aquí está la solución:
let
FindLoc= (lat, lon) =>
let
Source = Xml.Tables(Web.Contents("http://dev.virtualearth.net/REST/v1/Locations/"&Replacer.ReplaceText(Text.From(lat),",",".")&","&Replacer.ReplaceText(Text.From(lon),",",".")&"?o=xml&key=AqXbM3RmYA05LA89D0jBdRSYxgrYNUOwSNEsDS2G9aXaYBqFDOIYDT8IPoHKhJRp")),
#"Type modifié" = Table.TransformColumnTypes(Source,{{"Copyright", type text}, {"BrandLogoUri", type text}, {"StatusCode", Int64.Type}, {"StatusDescription", type text}, {"AuthenticationResultCode", type text}, {"TraceId", type text}}),
#"ResourceSets développé" = Table.ExpandTableColumn(#"Type modifié", "ResourceSets", {"ResourceSet"}, {"ResourceSets.ResourceSet"}),
#"ResourceSets ResourceSet" = #"ResourceSets développé"{0}[ResourceSets.ResourceSet],
#"Type modifié1" = Table.TransformColumnTypes(#"ResourceSets ResourceSet",{{"EstimatedTotal", Int64.Type}}),
Resources = #"Type modifié1"{0}[Resources],
Location = Resources{0}[Location]
in
#"Location"
in
FindLoc
Hi, @jsteffe ;
Puede verificar si estas publicaciones relacionadas pueden ser útiles para usted.
Uso de la API de Mapas de Bing para devolver latitud y longitud en Power Query – Wise Data Decisions
API de ubicaciones: | de Bing Maps Microsoft Learn
Saludos
Equipo de Apoyo a la Comunidad _ Yalan Wu
Si esta publicación ayuda, considere Aceptarlo como la solución para ayudar a los otros miembros a encontrarlo más rápidamente.
Cuando escribo la URL directamente, uso una coma entre lat y lon, pero si escribo mi función así, no funciona:
Text.From(lat)&"," &Text.From(lon)
Aquí está la solución:
let
FindLoc= (lat, lon) =>
let
Source = Xml.Tables(Web.Contents("http://dev.virtualearth.net/REST/v1/Locations/"&Replacer.ReplaceText(Text.From(lat),",",".")&","&Replacer.ReplaceText(Text.From(lon),",",".")&"?o=xml&key=AqXbM3RmYA05LA89D0jBdRSYxgrYNUOwSNEsDS2G9aXaYBqFDOIYDT8IPoHKhJRp")),
#"Type modifié" = Table.TransformColumnTypes(Source,{{"Copyright", type text}, {"BrandLogoUri", type text}, {"StatusCode", Int64.Type}, {"StatusDescription", type text}, {"AuthenticationResultCode", type text}, {"TraceId", type text}}),
#"ResourceSets développé" = Table.ExpandTableColumn(#"Type modifié", "ResourceSets", {"ResourceSet"}, {"ResourceSets.ResourceSet"}),
#"ResourceSets ResourceSet" = #"ResourceSets développé"{0}[ResourceSets.ResourceSet],
#"Type modifié1" = Table.TransformColumnTypes(#"ResourceSets ResourceSet",{{"EstimatedTotal", Int64.Type}}),
Resources = #"Type modifié1"{0}[Resources],
Location = Resources{0}[Location]
in
#"Location"
in
FindLoc
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