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Syndicate_Admin
Administrator
Administrator

Cómo ver dos columnas con CONTAINS STRING

Hola

Necesito agregar dos condiciones a una instrucción CONTAINS STRING pero no funciona. Agradecería si alguien puede ayudar, por favor.

Se vería algo como esto

Columna = IF( CONTAINSSTRING(('Tabla '[Columna] "A" && CONTAINSSTRING ('Tabla'[Columna] "B") "Y", "Z" ))
¡¡Gracias!!
1 ACCEPTED SOLUTION

Hay @Carrhill ,

Pruebe esto en su lugar:

Output = 
VAR _FindString01 = SEARCH("ABC", [Column1], 1, 0)
VAR _FindString02 = SEARCH("XYZ", [Column2], 1, 0)

RETURN IF(_FindString01 > 0 && _FindString02 > 0, "X", "Y")

Salida de ejemplo:

hnguy71_0-1651095551727.png

View solution in original post

4 REPLIES 4
Anonymous
Not applicable

Podrias usar tambien
= IF(CONTAINSSTRING(('Tabla'[Columna],"A")||CONTAINSSTRING ('Tabla'[Columna],"B"),"Y", "Z" )

 

Syndicate_Admin
Administrator
Administrator

@Carrhill , Prueba como

Columna = IF( CONTAINSSTRING('Tabla '[Columna] "A") || CONTAINSSTRING ('Tabla'[Columna] "B") || CONTAINSSTRING ('Tabla'[Columna] "Y")|| CONTAINSSTRING ('Tabla'[Columna] "Z") )

Hola @amitchandak ,

¡Gracias! Has resuelto el problema planteado. Sin embargo, no fui del todo claro en mi pregunta.

Este es mi objetivo...

Si la columna 1 contiene "abc" y la columna 2 contiene "xyz", devuelva X, de lo contrario Y

¿Hay alguna manera de hacer esto? ¡Gracias por su ayuda!

Hay @Carrhill ,

Pruebe esto en su lugar:

Output = 
VAR _FindString01 = SEARCH("ABC", [Column1], 1, 0)
VAR _FindString02 = SEARCH("XYZ", [Column2], 1, 0)

RETURN IF(_FindString01 > 0 && _FindString02 > 0, "X", "Y")

Salida de ejemplo:

hnguy71_0-1651095551727.png

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