Forum Discussion
RLS - one USERNAME() with access to multiple values in the same column
Hi everyone,
I have a case like this
| User 1 | Department 1 |
| User 1 | Department 2 |
| User 2 | Department 1 |
The data can also be structured like this
| User 1 | Department 1, Department 2 |
| User 2 | Department 1 |
I would like to setup RLS that User 1 can have access to both Deparment 1 and 2 but the Lookupvalue function only supports a single value result.
What should I do? Thank you so much in advance.
Hi Anonymous,
You can try this:
VAR A = CALCULATETABLE ( VALUES ( Table[Department] ), FILTER ( Table, Table[Username] = USERNAME () ) ) RETURN [Department] IN ABest Regards,
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If this post helps then please consider Accept it as the solution to help the other members find it more quickly.
4 Replies
- v-xulin-mstf
Community Support
Hi Anonymous,
You can try this:
VAR A = CALCULATETABLE ( VALUES ( Table[Department] ), FILTER ( Table, Table[Username] = USERNAME () ) ) RETURN [Department] IN ABest Regards,
Link
If this post helps then please consider Accept it as the solution to help the other members find it more quickly.
- AnonymousNot applicable
Thank you very much. That works perfectly.
- selimovd
Most Valuable Professional
Hey Anonymous ,
usually you would just filter the table to User = USERPRINCIPLENAME().
Then the report is filtered automatically to the departments the user has access to.
Would that work for your case?
If you need any help please let me know.If I answered your question I would be happy if you could mark my post as a solution ✔️ and give it a thumbs up 👍Best regardsDenisBlog: WhatTheFact.biFollow me: twitter.com/DenSelimovic- AnonymousNot applicable
Hi Denis,
Thank you for your reply. It didn't work as the lookup function only allow one single value as result. I actually tried this:
[Deparment] IN CALCULATETABLE (
VALUES (Table1[Department]),
Table1[User]=USERNAME()
)