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mina97
Helper III
Helper III

identifying in or out work hours based on am and pm timing

i have the following input data 7 / 31/ 2023  3: 49 :51 PM 

 

and my code  is identifying this as "in work hours"

what i am looking for is from 7 am to 3 pm equal" in work "

else "out of work"

please help and thank you

 

work hours = Switch(True() ,

[Date] >=Time(7,0,0) || [Date] <time(15,0,0), "Morning",

[Date] >=Time(15,0,0) ||  [Date] <= time(7,0,0), "Evening",

"Other"

)

 

 

1 ACCEPTED SOLUTION
JoeBarry
Solution Sage
Solution Sage

Hi @mina97 

 

DAX solution

 

In the table add a Column and name it as you will.

 

Add this

 

Column = IF(TIMEVALUE(RIGHT('Table'[Column1], 11)) >= TIME(7,0,0) && TIMEVALUE(RIGHT('Table'[Column1], 11)) < TIME(15,0,0) , "Morning", "Evening")

 

JoeBarry_0-1694080611078.png

 

Thanks

Joe

 

 

If this post helps, then please Accept it as the solution

 

View solution in original post

3 REPLIES 3
JoeBarry
Solution Sage
Solution Sage

Hi @mina97 

 

DAX solution

 

In the table add a Column and name it as you will.

 

Add this

 

Column = IF(TIMEVALUE(RIGHT('Table'[Column1], 11)) >= TIME(7,0,0) && TIMEVALUE(RIGHT('Table'[Column1], 11)) < TIME(15,0,0) , "Morning", "Evening")

 

JoeBarry_0-1694080611078.png

 

Thanks

Joe

 

 

If this post helps, then please Accept it as the solution

 

 

Column = IF(TIMEVALUE(RIGHT('Table'[Column1], 11)) >= TIME(7,0,0) && TIMEVALUE(RIGHT('Table'[Column1], 11)) < TIME(3,0,0) , "Morning", "Evening")

 

Column = IF(TIMEVALUE(RIGHT('Table'[Column1], 11)) >= TIME(7,0,0) && TIMEVALUE(RIGHT('Table'[Column1], 11)) < TIME(15,0,0) , "Morning", "Evening")

i tried the code but it does not work becase i have 3 am and 3 pm and it fails to distinguesh between them 

 

please help and thank you

I'm confused

 

In the original requirement, you needed to show between 7am and 3pm  My measure works for this 

Do you have other criteria for the measure besides between 7am and 3pm? 

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