Forum Discussion
millie23
2 years agoFrequent Visitor
Trying to do an if function with both contains and doesn't contain
I need something like:
if Text.Contains([Case Subject], "Word1", "Word2", "Word3", "Word4") or not Text.Contains([Case Subject], "Word5", "Word6") then 1 else 0)
I basically need an OR function here, and the goal is to basically add up the 1s when it comes to my visualisation. Can someone else?
Hi millie23,
Give this function a go
(string as text) => if List.Count( Splitter.SplitTextByAnyDelimiter({"Word1", "Word2", "Word3", "Word4"})(string)) >1 or List.Count( Splitter.SplitTextByAnyDelimiter({"Word5", "Word6"})(string)) =1 then 1 else 0Here's an example of how to implement that into your own code
let fxContains = (string as text) => if List.Count( Splitter.SplitTextByAnyDelimiter({"Word1", "Word2", "Word3", "Word4"})(string)) >1 or List.Count( Splitter.SplitTextByAnyDelimiter({"Word5", "Word6"})(string)) =1 then 1 else 0, myTable = #table({"Text"}, {{"Word1Up"}, {"2Word5"}, {"Fish"}}), AddCondition = Table.AddColumn( myTable, "test", each fxContains([Text])) in AddConditionHere's the output of that final query
I hope this is helpful
1 Reply
- m_dekorte
Resident Rockstar
Hi millie23,
Give this function a go
(string as text) => if List.Count( Splitter.SplitTextByAnyDelimiter({"Word1", "Word2", "Word3", "Word4"})(string)) >1 or List.Count( Splitter.SplitTextByAnyDelimiter({"Word5", "Word6"})(string)) =1 then 1 else 0Here's an example of how to implement that into your own code
let fxContains = (string as text) => if List.Count( Splitter.SplitTextByAnyDelimiter({"Word1", "Word2", "Word3", "Word4"})(string)) >1 or List.Count( Splitter.SplitTextByAnyDelimiter({"Word5", "Word6"})(string)) =1 then 1 else 0, myTable = #table({"Text"}, {{"Word1Up"}, {"2Word5"}, {"Fish"}}), AddCondition = Table.AddColumn( myTable, "test", each fxContains([Text])) in AddConditionHere's the output of that final query
I hope this is helpful