Forum Discussion

Anonymous's avatar
Anonymous
Not applicable
5 years ago
Solved

Transforming Null values based on Inserting text based another value of another column

Afternoon All,    I am having a challenge where trying to transform some of my data where I have blanks . Below is an example of some the data working with    Asset Name ISIN Product Cash ...
Need Help
  • Jakinta's avatar
    Jakinta
    5 years ago

    Will adding conditional custom column help?

     

     

    let
    Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("VY6xDoIwFEV/5aUzQ8UEdLQghKEJig4EHUip0oB9prQx/r2AkcTx5uaec6uK5AYbJyxE9dASjwC5ehXhF0epH6Qwtk9p7BtyNPaGvUIorDS90nfIYCcEpCwfZymjlG2SMt76wUwoWmleiA2ctbJwMm6wCz3j/zbW16I7ouggQm2VltrWPezd5K41ZFrgQ0LidAPxlH6+dRnyQ7iaGTFfvn651w8=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [#"Asset Name" = _t, ISIN = _t]),
    #"Changed Type" = Table.TransformColumnTypes(Source,{{"Asset Name", type text}, {"ISIN", type text}}),
    #"Added Custom" = Table.AddColumn(#"Changed Type", "Custom", each if Text.Contains([Asset Name], "Cash") then "Cash" else if Text.Contains([Asset Name], "Sherwood") then "No ISIN1" else if Text.Contains([Asset Name], "DM Property") then "No ISIN2" else [ISIN]),
    #"Removed Columns" = Table.RemoveColumns(#"Added Custom",{"ISIN"}),
    #"Renamed Columns" = Table.RenameColumns(#"Removed Columns",{{"Custom", "ISIN"}})
in
    #"Renamed Columns"

     

    or transform column version

     

    = Table.ReplaceValue(Source," ", each if Text.Contains([Asset Name],"Cash") then "Cash" else if Text.Contains([Asset Name],"Sherwood") then "No ISIN1" else if Text.Contains([Asset Name],"DM Property") then "No ISIN2" else [ISIN],Replacer.ReplaceText,{"ISIN"})

     

Anonymous's avatar
Anonymous
Not applicable
5 years ago

Jakinta 

Ideally would like to head down the transform route however when using your code , it does not seem to make any changes - Have tried using both "" and "null" withour any impact . Looks like the code runs but physically does not make any changes in the table 

 

 

  • Jakinta's avatar
    Jakinta
    Solution Sage
    5 years ago

    That is because you are trying to replace "null". There are no "null"s as texts, there are no nulls as objects in your column. I have used " ", since there is a blank space in your column to be replaced. At least in table you have posted initially.

    So try with " " or null, since I have no insight in your previous step.

    • Anonymous's avatar
      Anonymous
      Not applicable
      5 years ago

      as mention previous reply I have  tried using both "" and "null" withour any impact

      • Jakinta's avatar
        Jakinta
        Solution Sage
        5 years ago

        As i mentioned in previous reply  you did not try " "(not equal to "") or null ( not equal to "null"). 

        So we are dealing here with 4 different cases: 3 of them of type text, 1 of null type (green).