Round up date time column to remove miliseconds

This query will round secodrs for each column with type datetime. Is this what you want?
(You can remove my ChangedType step if you have already correct types defined)

Before

After

let
    Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("pdE9CsMwDAXgqxTPyUN/thytWUqvEDLkArn/WHfoVA8uFtoefIin40jE6+u6VyGxB1G05QwnT0snUoU7faL9SW00WzqXX4RDDMo0hWhwQa46iWjBJnOXWHAFU+8SC6lwG0KMIdordhzJwY5a5pDSHgTqvvgfJG/f9saQ8w0=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [#"Date / heure réception information" = _t, #"Date / Heure Premier Accès Acquittement" = _t, Site.Code = _t]),
    ChangedType = Table.TransformColumns(Source, {{"Date / heure réception information", DateTime.From}, {"Date / Heure Premier Accès Acquittement", DateTime.From}}),
    // Rouded seconds - only for columns with type datetime
    Transformed = Table.TransformColumns(ChangedType, List.Transform(Table.SelectRows(Table.Schema(ChangedType), each [Kind] = "datetime")[Name], (x)=> {x, each
        [ time = Time.From(_),
          hours = Time.Hour(time),
          minutes = Time.Minute(time),
          seconds = Number.Round(Time.Second(time)),
          result = Date.From(_) & Time.From((hours * 3600 + minutes * 60 + seconds) / 86400)
        ][result], type datetime}))
in
    Transformed