Remove text after any number

[non23]

How to get text in between Z and the last number? Here's a sample of the output that we want to achieve.

We were able to get the text after 'Z' but we can't seem to drop the letter after the number.

[wdx223_Daniel]

[Anonymous · Accepted solution]

Hi @non23 ,

Thank you for reaching out to the Microsoft Fabric Community.

I tried the following M Query on my end, and it worked successfully:

let

    textValue = [Data], 

    zPos = Text.PositionOf(textValue, "Z", Occurrence.First), 

    numbers = {"0".."9"},

    lastNumPos = List.Max(List.Transform(numbers, each Text.PositionOf(textValue, _, Occurrence.Last))), 

    start = if zPos = -1 then 0 else zPos + 1, 

    end = if lastNumPos = -1 then Text.Length(textValue) else lastNumPos + 1, 

    extractedText = Text.Middle(textValue, start, end - start) 

in

    extractedText

Since it worked for me, I am attaching a PBIX file to help you understand the setup better. If you need any further assistance, feel free to reach out.

If this post helps, then please give us Kudos and consider Accept it as a solution to help the other members find it more quickly.

Thank you. 

[Anonymous]

Hi @non23 ,

I wanted to check if you had the opportunity to review the information provided. Please feel free to contact us if you have any further questions. If my response has addressed your query, please accept it as a solution and give a 'Kudos' so other members can easily find it.

Thank you.

[Anonymous]

Hi @non23 ,

I wanted to follow up on our previous suggestions regarding the issue. We would love to hear back from you to ensure we can assist you further.

If my response has addressed your query, please accept it as a solution and give a ‘Kudos’ so other members can easily find it. Please let us know if there’s anything else we can do to help.

Thank you.

[Anonymous]

Hi @non23 ,

May I ask if you have resolved this issue? If so, please mark the helpful reply and accept it as the solution. This will be helpful for other community members who have similar problems to solve it faster.

Thank you.

[Omid_Motamedise]

You can use the following code into the advanced editor

let
    Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45Wcnb0sTSwcFOK1YlWikLmWBgYQASdghydvQ2MlWJjAQ==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Data = _t]),
    #"Added Custom" = Table.AddColumn(Source, "Custom", each Splitter.SplitTextByCharacterTransition({"0".."9"},{"a".."z","A".."Z"})([Data]){0})
in
    #"Added Custom"

[MarkLaf]

The function that does most of the work for you in this scenario would be Text.PositionOfAny

Here is some M for handling all your logic in one AddColumn step. I included some logic for handling cases when there is no Z and/or no numbers

let
    Source = PreviousTransforms,

    //Adds column that provides text between first Z (exclusive) and last number (inclusive)
    AddBetweenZandNum = 
    Table.AddColumn(
        Source, 
        "BetweenZandNum", 
        each let 
            posOfLastNum = Text.PositionOfAny( [Data], {"0".."9"}, Occurrence.Last ), 
            posOfZ =  Text.PositionOf( [Data], "Z", Occurrence.First ), 
            start = List.Max( { 0, posOfZ } ), 
            end = if posOfLastNum = -1 then Text.Length( [Data] ) else posOfLastNum
        in 
            Text.Middle( [Data], start, 1 + end - start ), 
        type text
    )
in
    AddBetweenZandNum

 Output

[Akash_Varuna]

Hi @non23 I suppose there are input withot Z also .... To achive this create a calculated column with the formula given

Text.Select(
    Text.BeforeDelimiter(Text.Combine({[Data], "Z"}), "Z"),
    {"A".."Z", "0".."9"}
)