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longlongisi's avatar
longlongisi
Frequent Visitor
10 months ago
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New Measure-IF statement with 2 columns

Hi All I would like to have a meaure, if " Accessories_Treats" is Treats, & "Item Number " is duplicate, then =1. For 2134, only 1 row is " Treats", then it is 0, whole 2345, 2 rows are treats, the...
  • Nabha-Ahmed's avatar
    10 months ago

    Hi   

     

    you can flag rows where an Item Number has more than one "Treats" row and mark those "Treats" rows with 1(otherwise 0).
    Below are two options: a measure (dynamic, recommended in visuals) and a calculated column (stored at refresh).

    Replace YourTable with your actual table name.

    Measure (recommended for visuals):

     

     
    Treats_Duplicate_Flag_Measure =
    VAR ThisItem = SELECTEDVALUE(YourTable[Item Number])
    VAR ThisRowIsTreat = SELECTEDVALUE(YourTable[Accessories_Treats]) = "Treats"
    VAR NumTreatsForItem =
    CALCULATE(
    COUNTROWS(YourTable),
    FILTER(
    ALL(YourTable),
    YourTable[Item Number] = ThisItem
    && YourTable[Accessories_Treats] = "Treats"
    )
    )
    RETURN
    IF(ThisRowIsTreat && NumTreatsForItem > 1, 1, 0)
    • Put Item Number, Amount and this measure in a table visual — each row where Accessories_Treats = "Treats"and the item has more than one Treats will show 1.

      Calculated column (if you prefer a stored column):

      Treats_Duplicate_Flag_Measure =
      VAR ThisItem = SELECTEDVALUE(YourTable[Item Number])
      VAR ThisRowIsTreat = SELECTEDVALUE(YourTable[Accessories_Treats]) = "Treats"
      VAR NumTreatsForItem =
      CALCULATE(
      COUNTROWS(YourTable),
      FILTER(
      ALL(YourTable),
      YourTable[Item Number] = ThisItem
      && YourTable[Accessories_Treats] = "Treats"
      )
      )
      RETURN
      IF(ThisRowIsTreat && NumTreatsForItem > 1, 1, 0)

      • This column is computed at data refresh and can be used for filtering/grouping without recomputation at report runtime.

         

        Thanks 🌹

        put kudo

         

         

         

    longlongisi