Forum Discussion
How to group row values for distinct count
Data table includes columns for email addresses, name of email sent and column that identifies whether it was opened or not (True\False valuse) I want to create a chart that shows; count of distinct email addresses that did not open any of the email names sent to their email address.
Example below distinct count would be 0 since email address opened at least 1 email.
| Email address | email name | opened |
| xyz.com | Apples | False |
| xyz.com | Bannanas | False |
| xyz.com | Oranges | True |
2nd example below, distinct count to be 1 since email address did not open any emails.
| Email address | email name | Opened |
| abc.com | Apples | False |
| abc.com | Bannanas | False |
| abc.com | Oragnes | False |
Hi Anonymous
You talk about a chart but mention only one dimension you want to show? Place this measure in a card visual:
Measure = COUNTROWS ( FILTER ( DISTINCT ( Table1[EmailAddress] ), CALCULATE ( SUMX ( Table1, Table1[Opened] * 1 ) ) = 0 ) )Please mark the question solved when done and consider giving a thumbs up if posts are helpful.
Contact me privately for support with any larger-scale BI needs, tutoring, etc.
Cheers
Hi Anonymous ,
Based on your description, you can create a measure like this:
Distinct = IF ( COUNTX ( FILTER ( ALL ( 'Table' ), 'Table'[Email address] IN DISTINCT ( 'Table'[Email address] ) && 'Table'[opened] = TRUE () ), [Email address] ) >= 1, 0, CALCULATE ( DISTINCTCOUNT ( 'Table'[Email address] ), FILTER ( ALL ( 'Table' ), 'Table'[Email address] IN DISTINCT ( 'Table'[Email address] ) ) ) )Attached a sample file in the below, hopes to help you.
Best Regards,
Community Support Team _ Yingjie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
3 Replies
- AlBCommunity Champion
Hi Anonymous
You talk about a chart but mention only one dimension you want to show? Place this measure in a card visual:
Measure = COUNTROWS ( FILTER ( DISTINCT ( Table1[EmailAddress] ), CALCULATE ( SUMX ( Table1, Table1[Opened] * 1 ) ) = 0 ) )Please mark the question solved when done and consider giving a thumbs up if posts are helpful.
Contact me privately for support with any larger-scale BI needs, tutoring, etc.
Cheers
- v-yingjlCommunity Support
Hi Anonymous ,
Based on your description, you can create a measure like this:
Distinct = IF ( COUNTX ( FILTER ( ALL ( 'Table' ), 'Table'[Email address] IN DISTINCT ( 'Table'[Email address] ) && 'Table'[opened] = TRUE () ), [Email address] ) >= 1, 0, CALCULATE ( DISTINCTCOUNT ( 'Table'[Email address] ), FILTER ( ALL ( 'Table' ), 'Table'[Email address] IN DISTINCT ( 'Table'[Email address] ) ) ) )Attached a sample file in the below, hopes to help you.
Best Regards,
Community Support Team _ Yingjie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.- AnonymousNot applicable
Thank you for your help. I appreciate you.