Forum Discussion

Sayri's avatar
Sayri
Helper I
5 years ago
Solved

How to extract all the column names from a 'Table' data Type Column ?

Hi all,
Would it be possible to extract all the column names + 1st row, from each Table listed in 'Data' Column below please ?



The goal would be to have a list like:

Index0.Column01, 1st row Value
Index0.Column02, 1st row Value
Index0.Column03, 1st row Value
Index1.Column1, 1st row Value
Index1.Column2, 1st row Value
Index1.Column3, 1st row Value
Index2.ColumnA, 1st row Value
Index2.ColumnB, 1st row Value
Index2.ColumnC, 1st row Value
Index2.ColumnD, 1st row Value
Index3.Column1a, 1st row Value
Index3.Column2b, 1st row Value
Etc...

  • Hi, Sayri , it's easy to extract all columns' names from each table in your scenario; you might add applied steps like this,

     

    #"Column Names" = Table.TransformColumns(#"Previous Step", {{"Data", Table.ColumnNames}}),
    #"Expanded Data" = Table.ExpandListColumn(#"Column Names", "Data")

     

  • Hello Sayri 

     

    you can transform you tables first to get the first row of your tables as new table with Table.First and Record.ToTable.

    Then expand the newly created table. here an easy example

     

    let
        Source = #table({"Index", "Data"}, {{"Index0", #table({"ColumnA", "ColumnB"}, {{"A", "B"}, {"C", "D"}})}, {"Index1", #table({"Column1", "Column2"}, {{"E", "F"}, {"G", "H"}})}}),
        GetFirstRowOfTable = Table.TransformColumns
        (
            Source,
            {
                {
                    "Data",
                    each Record.ToTable(Table.First(_))
                }
            }
        ),
        #"Expanded Data" = Table.ExpandTableColumn(GetFirstRowOfTable, "Data", {"Name", "Value"}, {"Column name", "First row value"})
    in
        #"Expanded Data"

     

     

    Copy paste this code to the advanced editor in a new blank query to see how the solution works.

    If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
    Kudoes are nice too

    Have fun

    Jimmy

5 Replies

  • CNENFRNL's avatar
    CNENFRNL
    Community Champion

    Hi, Sayri , it's easy to extract all columns' names from each table in your scenario; you might add applied steps like this,

     

    #"Column Names" = Table.TransformColumns(#"Previous Step", {{"Data", Table.ColumnNames}}),
    #"Expanded Data" = Table.ExpandListColumn(#"Column Names", "Data")

     

    • Sayri's avatar
      Sayri
      Helper I

      Thanks a lot CNENFRNL , your solution works perfectly to list the column names 🙂
      Is there any possibility to extract the 1st value of each colomn for each table please ?

  • wdx223_Daniel's avatar
    wdx223_Daniel
    Community Champion

    =#table(2,List.Combine(Table.ToList(PreviousStep,each List.Transform(Table.ColumnNames(_{1}),(x)=>Number.ToText(_{0},"Index0.")&x&","&Record.FieldOfDefault(_{1}{0},x,null)))))

  • Jimmy801's avatar
    Jimmy801
    Community Champion

    Hello Sayri 

     

    you can transform you tables first to get the first row of your tables as new table with Table.First and Record.ToTable.

    Then expand the newly created table. here an easy example

     

    let
        Source = #table({"Index", "Data"}, {{"Index0", #table({"ColumnA", "ColumnB"}, {{"A", "B"}, {"C", "D"}})}, {"Index1", #table({"Column1", "Column2"}, {{"E", "F"}, {"G", "H"}})}}),
        GetFirstRowOfTable = Table.TransformColumns
        (
            Source,
            {
                {
                    "Data",
                    each Record.ToTable(Table.First(_))
                }
            }
        ),
        #"Expanded Data" = Table.ExpandTableColumn(GetFirstRowOfTable, "Data", {"Name", "Value"}, {"Column name", "First row value"})
    in
        #"Expanded Data"

     

     

    Copy paste this code to the advanced editor in a new blank query to see how the solution works.

    If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
    Kudoes are nice too

    Have fun

    Jimmy

    • Sayri's avatar
      Sayri
      Helper I

      Actually I've done a mix between your solution and the previous from CNENFRNL  and it works perfectly
      Thank you very much to both of you