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huynq's avatar
huynq
Frequent Visitor
6 years ago
Solved

How to count values of columns???

Hi everyone, I'm sorry for my bad English. I've tried to find the solution for this but didn't work so I post this message for your help.

I have this data:

 

A  B  C  D

a  b  c  d

a  b  a  a

c  a  d  o

 

What I'm looking for
     A  B  C  D
a   2  1  1  1

b   0  2  0  0

c   1  0  1  0

d   0  0  1  1

o   0  0  0  1

 

I would like to say thanks in advance. 

  • Hello huynq 

     

    this involves some unpivoting, grouping and pivoting. Check out this code example

    let
    	Source = #table 
    	(
    		{ "A", "B", "C", "D" },
    		{ { "a", "b", "c", "d" }, { "a", "b", "a", "a" }, { "c", "a", "d", "o" } } 
    	),
    	Unpivot = Table.UnpivotOtherColumns 
    	(
    		Source,
    		{ },
    		"Attribute",
    		"Value" 
    	),
    	Group = Table.Group 
    	(
    		Unpivot,
    		{ "Attribute", "Value" },
    		{ { "Count", each Table.RowCount ( _ ), type number } } 
    	),
    	Pivot = Table.Pivot 
    	(
    		Group,
    		List.Distinct 
    		(
    			Group [ Attribute ] 
    		),
    		"Attribute",
    		"Count",
    		List.Sum 
    	)
     in 
    	Pivot

     

    Copy paste this code to the advanced editor in a new blank query to see how the solution works. If this solution fits your need, copy and past a part of it and implement it in your query, or I could create a custom function what makes it easier to apply if you are not used that much to power query.

    If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
    Kudoes are nice too

    Have fun

    Jimmy

  • Hello huynq 

     

    just use this code instead

    let
    	Source = #table 
    	(
    		{ "A", "B", "C", "D" },
    		{ { "a", "b", "c", "d" }, { "a", "b", "a", "a" }, { "c", "a", "d", "o" } } 
    	),
    	Unpivot = Table.UnpivotOtherColumns 
    	(
    		Source,
    		{ },
    		"Attribute",
    		"Value" 
    	),
    	Group = Table.Group 
    	(
    		Unpivot,
    		{ "Attribute", "Value" },
    		{ { "Count", each Table.RowCount ( _ ), type number } } 
    	),
    	Pivot = Table.Pivot 
    	(
    		Group,
    		List.Distinct 
    		(
    			Group [ Attribute ] 
    		),
    		"Attribute",
    		"Count",
    		each if List.IsEmpty(_) then 0 else List.Sum (_)
    	)
     in 
    	Pivot

     

    If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
    Kudoes are nice too

    Have fun

    Jimmy

4 Replies

  • Jimmy801's avatar
    Jimmy801
    Icon for Community Champion rankCommunity Champion

    Hello huynq 

     

    this involves some unpivoting, grouping and pivoting. Check out this code example

    let
    	Source = #table 
    	(
    		{ "A", "B", "C", "D" },
    		{ { "a", "b", "c", "d" }, { "a", "b", "a", "a" }, { "c", "a", "d", "o" } } 
    	),
    	Unpivot = Table.UnpivotOtherColumns 
    	(
    		Source,
    		{ },
    		"Attribute",
    		"Value" 
    	),
    	Group = Table.Group 
    	(
    		Unpivot,
    		{ "Attribute", "Value" },
    		{ { "Count", each Table.RowCount ( _ ), type number } } 
    	),
    	Pivot = Table.Pivot 
    	(
    		Group,
    		List.Distinct 
    		(
    			Group [ Attribute ] 
    		),
    		"Attribute",
    		"Count",
    		List.Sum 
    	)
     in 
    	Pivot

     

    Copy paste this code to the advanced editor in a new blank query to see how the solution works. If this solution fits your need, copy and past a part of it and implement it in your query, or I could create a custom function what makes it easier to apply if you are not used that much to power query.

    If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
    Kudoes are nice too

    Have fun

    Jimmy

    • huynq's avatar
      huynq
      Frequent Visitor

      You are the life savior, by the way how can I replace null value by 0? 

      • Jimmy801's avatar
        Jimmy801
        Icon for Community Champion rankCommunity Champion

        Hello huynq 

         

        just use this code instead

        let
        	Source = #table 
        	(
        		{ "A", "B", "C", "D" },
        		{ { "a", "b", "c", "d" }, { "a", "b", "a", "a" }, { "c", "a", "d", "o" } } 
        	),
        	Unpivot = Table.UnpivotOtherColumns 
        	(
        		Source,
        		{ },
        		"Attribute",
        		"Value" 
        	),
        	Group = Table.Group 
        	(
        		Unpivot,
        		{ "Attribute", "Value" },
        		{ { "Count", each Table.RowCount ( _ ), type number } } 
        	),
        	Pivot = Table.Pivot 
        	(
        		Group,
        		List.Distinct 
        		(
        			Group [ Attribute ] 
        		),
        		"Attribute",
        		"Count",
        		each if List.IsEmpty(_) then 0 else List.Sum (_)
        	)
         in 
        	Pivot

         

        If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
        Kudoes are nice too

        Have fun

        Jimmy