Forum Discussion
How to add a custom column with surrogate grouping
Hi all,
I would like to add a (very simple) column to a table to create surrogate groups that I can then use to pivot the data. The current table does not contain any data that I can use for this, so Power Query does not understand how to pivot.
Basically, I need to add the following column to my table:
Group
1
1
1
2
2
2
3
3
3
4
4
4
etc.
Is there a way to do that with an M function?
Thanks!
Bas
Hi kirvis - Take a look at this code:
let Source = {1..100}, #"Converted to Table" = Table.FromList(Source, Splitter.SplitByNothing(), null, null, ExtraValues.Error), #"Added Index" = Table.AddIndexColumn(#"Converted to Table", "Index", 1, 1/3, Int64.Type), #"Inserted Round Down" = Table.AddColumn(#"Added Index", "Round Down", each Number.RoundDown(Number.Round([Index],8)), Int64.Type) in #"Inserted Round Down"What I did is:
- Create a fake column of 1 to 100 just to have some data.
- Added an index. Then I changed the index to start at 1 and increment by 1/3.
- Then I added a column with this formula: Number.RoundDown(Number.Round([Index],8))
It returns this:
How to use M code provided in a blank query:
1) In Power Query, select New Source, then Blank Query
2) On the Home ribbon, select "Advanced Editor" button
3) Remove everything you see, then paste the M code I've given you in that box.
4) Press Done
5) See this article if you need help using this M code in your model.
6 Replies
- Bohumil_UhrinHelper II
Hi,
firstly, add normal index column, name it "Index", starting from 0
then add this step:
= Table.TransformColumns(previous_table, {{"Index", each Number.IntegerDivide(_, 3), Int64.Type}})
- edhansCommunity Champion
Hi kirvis - Take a look at this code:
let Source = {1..100}, #"Converted to Table" = Table.FromList(Source, Splitter.SplitByNothing(), null, null, ExtraValues.Error), #"Added Index" = Table.AddIndexColumn(#"Converted to Table", "Index", 1, 1/3, Int64.Type), #"Inserted Round Down" = Table.AddColumn(#"Added Index", "Round Down", each Number.RoundDown(Number.Round([Index],8)), Int64.Type) in #"Inserted Round Down"What I did is:
- Create a fake column of 1 to 100 just to have some data.
- Added an index. Then I changed the index to start at 1 and increment by 1/3.
- Then I added a column with this formula: Number.RoundDown(Number.Round([Index],8))
It returns this:
How to use M code provided in a blank query:
1) In Power Query, select New Source, then Blank Query
2) On the Home ribbon, select "Advanced Editor" button
3) Remove everything you see, then paste the M code I've given you in that box.
4) Press Done
5) See this article if you need help using this M code in your model. - PhilipTreacySuper User
Hi kirvis
If you want the numbers in the column to start from 1 just use Bohumil_Uhrin solution and add 1 after the Number.IntegerDivide
= Table.TransformColumns(previous_table, {{"Index", each Number.IntegerDivide(_, 3) + 1, Int64.Type}})Phil
- Jimmy801Community Champion
Hello kirvis
here another approach if you are interested in
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WSixOSVOK1YlWKk5MAdNwHoSBKV+cCKbR5ROLcQgjG0u6bUQZi0e/UmwsAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [#"Your Column" = _t]), #"Changed Type" = Table.TransformColumnTypes(Source,{{"Your Column", type text}}), SplitTable = Table.FromList(Table.Split(#"Changed Type",3), Splitter.SplitByNothing(), null, null, ExtraValues.Error), AddIndex = Table.AddIndexColumn(SplitTable, "Group", 1, 1), ExpandTable = Table.ExpandTableColumn(AddIndex, "Column1", {"Your Column"}, {"Your Column"}) in ExpandTableCopy paste this code to the advanced editor in a new blank query to see how the solution works.
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Kudoes are nice too
Have fun
Jimmy