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Anonymous's avatar
Anonymous
Not applicable
3 years ago
Solved

Group data/ alternative Row transfer into column

I want to re-organize the data as below. Every 2 rows will be transposed and all data need to convert into 02 columns.     
Need Help
  • wdx223_Daniel's avatar
    wdx223_Daniel
    3 years ago

    NewStep=#table(2,List.TransformMany(Table.Split(PreviousStepName,2),each Table.ToColumns(_),(x,y)=>y))

    if you use the source as your another post, just use this code to get result in one step

    =let fx=(t)=>let a=Text.Split(Text.From(t)??"","-") in List.Count(a)=3 and List.AllTrue(List.Transform(a,each _<>"" and Text.Remove(_,{"0".."9"})="")) in #table(2,List.Accumulate(Table.ToRows(PreviousStepName),{{},{}},(x,y)=>{x{0}&List.Select(List.Zip({x{1},y}),each fx(_{1})),y}){0})

wdx223_Daniel's avatar
wdx223_Daniel
Community Champion
3 years ago

NewStep=#table(2,List.TransformMany(Table.Split(PreviousStepName,2),each Table.ToColumns(_),(x,y)=>y))

if you use the source as your another post, just use this code to get result in one step

=let fx=(t)=>let a=Text.Split(Text.From(t)??"","-") in List.Count(a)=3 and List.AllTrue(List.Transform(a,each _<>"" and Text.Remove(_,{"0".."9"})="")) in #table(2,List.Accumulate(Table.ToRows(PreviousStepName),{{},{}},(x,y)=>{x{0}&List.Select(List.Zip({x{1},y}),each fx(_{1})),y}){0})