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Anonymous's avatar
Anonymous
Not applicable
6 years ago
Solved

Find alphabetical letters from a string

Hi,

 

I need to be able to extract MT940 (type :61:) sums from the string. Basically the issue is that i have the following:

 

1911011101C5555,55NTRF201911015U//SOM 19111503828

 

What i need to extract to a column is the value 5555,55 right after C.

- The amount of numbers before C is always the same. 

- The number 5555,55 can be anything, its the amount deposited or drafted from a bank account

- There is always an alphabetical value after the wanted value of 5555,55€, but the lenght of the variables behind 5555,55 are not constant.

 

I would imagine that is solved by 

1. Splitting the column by taking away first 11 characters.

2. Finding the position of the first alphabetical figure.

3. Extracting the values before the first alphabetical figure.

 

>> How do i find the first alphabetical figure in Power Query of a string? I've been googling this forever without a result..

 

Need Help
  • Anonymous's avatar
    Anonymous
    6 years ago

    This expression will break up a string into a list based on alpha characters.

     

    Text.SplitAny([nameofstringhere],Text.Combine({"a".."z","A".."Z"}))

     

    Now just reference the second value with the index of {1}

    Text.SplitAny([nameofstringhere],Text.Combine({"a".."z","A".."Z"})){1}

3 Replies

  • Anonymous's avatar
    Anonymous
    Not applicable
    6 years ago

    This expression will break up a string into a list based on alpha characters.

     

    Text.SplitAny([nameofstringhere],Text.Combine({"a".."z","A".."Z"}))

     

    Now just reference the second value with the index of {1}

    Text.SplitAny([nameofstringhere],Text.Combine({"a".."z","A".."Z"})){1}

  • Greg_Deckler's avatar
    Greg_Deckler
    Community Champion
    6 years ago

    ImkeF  can likely help with the Power Query. One method you might be able to use in DAX assuming you always have 2 decimal points would be something like:

    Column = 
    VAR __Start = 12
    VAR __Decimal = FIND(",",[Column1],__Start,LEN([Column1]) - __Start - 1)
RETURN
    MID([Column1],__Start,__Decimal -__Start + 3)

     

  • Jimmy801's avatar
    Jimmy801
    Community Champion
    6 years ago

    Hello Anonymous ,

     

    check out this solution.

    Basically it eliminates the first 11 character and then extracts characters er as long numbers, "." and "," are found

    let
    Quelle = "1911011101C5555,55NTRF201911015U//SOM 19111503828",
    startnumber = Text.End
    (
        Quelle,
        Text.Length(Quelle)-11
    ),
    ListText = Text.ToList
    (
        startnumber
    ),
    GoUntilNotNumberOrComma = List.FirstN
    (
        ListText,
        (val) =>
            let 
                isnumber = try if Value.Is(Number.From(val),type number)= true then true else false otherwise false,
                iscomma = if val = "," then true else false ,
                ispoint = if val = "." then true else false,
                partofnumber = if isnumber = true or iscomma = true or ispoint = true then true else false
            in 
                partofnumber
    ),
    ConvertToText = Lines.ToText(GoUntilNotNumberOrComma, "")
in
    ConvertToText

     

    Copy paste this code to the advanced editor to see how the solution works

    If this post helps or solves your problem, please mark it as solution.
    Kudos are nice to - thanks
    Have fun

    Jimmy